[c++] In c++ what does a tilde "~" before a function name signify?

 template <class T>
 class Stack
 {
 public:
    Stack(int = 10) ; 
    ~Stack() { delete [] stackPtr ; }  //<--- What does the "~" signify?
    int push(const T&); 
    int pop(T&) ;  
    int isEmpty()const { return top == -1 ; } 
    int isFull() const { return top == size - 1 ; } 
 private:
    int size ;  
    int top ;  
    T* stackPtr ;  
 } ;

That would be the destructor(freeing up any dynamic memory)

It's a destructor. The function is guaranteed to be called when the object goes out of scope.

This is a destructor. It's called when the object is destroyed (out of life scope or deleted).

To be clear, you have to use ~NameOfTheClass like for the constructor, other names are invalid.

As others have noted, in the instance you are asking about it is the destructor for class Stack.

But taking your question exactly as it appears in the title:

In c++ what does a tilde “~” before a function name signify?

there is another situation. In any context except immediately before the name of a class (which is the destructor context), ~ is the one's complement (or bitwise not) operator. To be sure it does not come up very often, but you can imagine a case like

if (~getMask()) { ...

which looks similar, but has a very different meaning.

It's the destructor. This method is called when the instance of your class is destroyed:

Stack<int> *stack= new Stack<int>;
//do something
delete stack; //<- destructor is called here;