In jQuery, $("...").get(3) returns the 3rd DOM element. What is the function to return the 3rd jQuery element?
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If I understand your question correctly, you can always just wrap the get function like so:
var $someJqueryEl = $($('.myJqueryEls').get(3));
.eq() -An integer indicating the 0-based position of the element.
Ex:
Consider a page with a simple list on it:
<ul>
<li>list item 1</li>
<li>list item 2</li>
<li>list item 3</li>
<li>list item 4</li>
</ul>
We can apply this method to the set of list items:
$( "li" ).eq( 2 ).css( "background-color", "red" );
if you have control over the query which builds the jQuery object, use :eq()
$("div:eq(2)")
If you don't have control over it (for example, it's being passed from another function or something), then use .eq()
var $thirdElement = $jqObj.eq(2);
Or if you want a section of them (say, the third, fourth and fifth elements), use .slice()
var $third4th5thElements = $jqObj.slice(2, 5);
If you already have the jquery object in a variable, you can also just treat it as a normal indexed array, without the use of jquery:
var all_rows = $("tr");
for(var i=0; i < all_rows.length; i++){
var row = all_rows[i];
//additionally, you can use it again in a jquery selector
$(row).css("background-color","black");
}
Although the above example is not useful in any way, it is representing how you can treat objects created by jquery as indexed arrays.
$(function(){
$(document).find('div').siblings().each(function(){
var obj = $(this);
obj.find('div').each(function(){
var obj1 = $(this);
if(!obj1.children().length > 0){
alert(obj1.html());
}
});
});
});
<div id="2">
<div>
<div>
<div>XYZ Pvt. Ltd.</div>
</div>
</div>
</div>
<div id="3">
<div>
<div>
<div>ABC Pvt Ltd.</div>
</div>
</div>
</div>
For iterations using a selector doesn't seem to make any sense though:
var some = $( '...' );
for( i = some.length -1; i>=0; --i )
{
// Have to transform in a jquery object again:
//
var item = $( some[ i ] );
// use item at will
// ...
}
If you want to fetch particular element/node or tag in loop for e.g.
<p class="weekday" data-today="monday">Monday</p>
<p class="weekday" data-today="tuesday">Tuesday</p>
<p class="weekday" data-today="wednesday">Wednesday</p>
<p class="weekday" data-today="thursday">Thursday</p>
So, from above code loop is executed and we want particular field to select for that we have to use jQuery selection that can select only expecting element from above loop so, code will be
$('.weekdays:eq(n)');
e.g.
$('.weekdays:eq(0)');
as well as by other method
$('.weekday').find('p').first('.weekdays').next()/last()/prev();
but first method is more efficient when HTML <tag> has unique class name.
NOTE:Second method is use when their is no class name in target element or node.
for more follow https://api.jquery.com/eq/
<html>
<head></head>
<body>
<script type="text/javascript"
src="http://code.jquery.com/jquery-2.1.0.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('li:eq(1)').hide();
});
</script>
<ol>
<li>First</li>
<li>Second</li>
<li>Third</li>
</ol>
</body>
</html>
When it runs, there are two items in the ordered list that show, First, and Third. The second was hidden.
I think you can use this
$("ul li:nth-child(2)").append("<span> - 2nd!</span>");
It finds the second li in each matched ul and notes it.
Source: Stackoverflow.com