How to avoid scientific notation for large numbers in JavaScript

Question

JavaScript converts a large INT to scientific notation when the number becomes large  How can I prevent this from happening

User · Answer

function printInt n    return n toPrecision 100  replace                 with some issues    0 9 is displayed as  0  -0 9 is displayed as  -0  1e100 is displayed as  1  works only for numbers up to  1e99    use other constant for greater numbers  or smaller for optimization

User · Answer

one more possible solution   function toFix i    var str      do     let a   i 10     i Math trunc i 10      str   a str    while i gt 0   return str

User · Answer

There s Number toFixed  but it uses scientific notation if the number is    1e21 and has a maximum precision of 20  Other than that  you can roll your own  but it will be messy   function toFixed x      if  Math abs x   lt  1 0        var e   parseInt x toString   split  e-   1        if  e            x    Math pow 10 e-1           x    0      new Array e   join  0     x toString   substring 2             else       var e   parseInt x toString   split      1        if  e  gt  20            e -  20          x    Math pow 10 e           x     new Array e 1   join  0                return x      Above uses cheap- n -easy string repetition   new Array n 1   join str    You could define String prototype repeat using Russian Peasant Multiplication and use that instead   This answer should only be applied to the context of the question  displaying a large number without using scientific notation  For anything else  you should use a BigInt library  such as BigNumber  Leemon s BigInt  or BigInteger  Going forward  the new native BigInt  note  not Leemon s  should be available  Chromium and browsers based on it  Chrome  the new Edge  v79    Brave  and Firefox all have support  Safari s support is underway   Here s how you d use BigInt for it  BigInt n  toString    Example    x000D   x000D  const n   13523563246234613317632  x000D  console log  toFixed  wrong       n toFixed     x000D  console log  BigInt  right        BigInt n  toString     x000D   x000D   x000D    Beware  though  that any integer you output as a JavaScript number  not a BigInt  that s more than 15-16 digits  specifically  greater than Number MAX SAFE INTEGER   1  9 007 199 254 740 992   may be be rounded  because JavaScript s number type  IEEE-754 double-precision floating point  can t precisely hold all integers beyond that point  As of Number MAX SAFE INTEGER   1 it s working in multiples of 2  so it can t hold odd numbers anymore  and similiarly  at 18 014 398 509 481 984 it starts working in multiples of 4  then 8  then 16         Consequently  if you can rely on BigInt support  output your number as a string you pass to the BigInt function   const n   BigInt  YourNumberHere      Example    x000D   x000D  const n1   BigInt 18014398509481985      WRONG  will round to 18014398509481984 x000D                                           before  BigInt  sees it x000D  console log n1 toString        lt    WRONG    x000D  const n2   BigInt  18014398509481985       RIGHT  BigInt handles it x000D  console log n2 toString        lt    Right    x000D   x000D   x000D

User · Answer

I tried working with the string form rather than the number and this seemed to work  I have only tested this on Chrome but it should be universal   function removeExponent s        var ie   s indexOf  e        if  ie    -1            if  s charAt ie   1      -                    negative exponent  prepend with  0s             var n   s substr ie   2  match   0-9                  s   s substr 2  ie - 2      remove the leading  0   and exponent chars             for  var i   0  i  lt  n  i                      s    0    s                            s         s            else                  positive exponent  postpend with 0s             var n   s substr ie   1  match   0-9                  s   s substr 0  ie      strip off exponent chars                         for  var i   0  i  lt  n  i                      s     0                                            return s

User · Answer

Busting out the regular expressions  This has no precision issues and is not a lot of code   x000D   x000D  function toPlainString num      return       num  replace   -    d       d  e   -  d         function a b c d e          return e  lt  0           b    0     Array 1-e-c length  join 0    c   d           b   c   d   Array e-d length 1  join 0              console log toPlainString 12345e 12    console log toPlainString 12345e 24    console log toPlainString -12345e 24    console log toPlainString 12345e-12    console log toPlainString 123e-12    console log toPlainString -123e-12    console log toPlainString -123 45e-56    console log toPlainString  1e-8     console log toPlainString  1 0e-8     x000D   x000D   x000D

User · Answer

I know this is an older question  but shows recently active  MDN toLocaleString  const myNumb   1000000000000000000000  console log  myNumb       1e 21 console log  myNumb toLocaleString          1 000 000 000 000 000 000 000  console log  myNumb toLocaleString  fullwide    useGrouping false          1000000000000000000000    you can use options to format the output   Note   Number toLocaleString   rounds after 16 decimal places  so that     const myNumb   586084736227728377283728272309128120398  console log  myNumb toLocaleString  fullwide     useGrouping  false            returns     586084736227728400000000000000000000000  This is perhaps undesirable if accuracy is important in the intended result

User · Answer

You can use number toString 10 1    console log Number MAX VALUE toString 10 1      Note  This currently works in Chrome  but not in Firefox  The specification says the radix has to be an integer  so this results in unreliable behavior

User · Answer

This is what I ended up using to take the value from an input  expanding numbers less than 17digits and converting Exponential numbers to x10y     e g      niceNumber  1 24e 4     becomes     1 24x10 to the power of 4  displayed in Superscript   function niceNumber num      try          var sOut   num toString          if   sOut length  gt  17    sOut indexOf  e    gt  0         sOut parseFloat num  toPrecision 5            sOut   sOut replace  e   x10 lt sup gt      lt  sup gt                  return sOut         catch   e          return num

User · Answer

You can loop over the number and achieve the rounding        functionality to replace char at given index   String prototype replaceAt function index  character        return this substr 0  index    character   this substr index character length             looping over the number starts   var str    123456789123456799 55   var arr   str split       str   arr 0   i    str length-1   if arr 1  length  amp  amp  Math round arr 1  100      while i gt 0       var intVal   parseInt str charAt i        if intVal    9         str   str replaceAt i  0          console log 1 str      else        str   str replaceAt i  intVal 1  toString            console log 2 i  intVal 1  toString   str        break          i--

User · Answer

The question of the post was avoiding e notation numbers and having the number as a plain number  Therefore  if all is needed is to convert e  scientific  notation numbers to plain numbers  including in the case of fractional numbers  without loss of accuracy  then it is essential to avoid the use of the Math object and other javascript number methods so that rounding does not occur when large numbers and large fractions are handled  which always happens due to the internal storage in binary format   The following function converts e  scientific  notation numbers to plain numbers  including fractions  handling both large numbers and large fractions without loss of accuracy as it does not use the built-in math and number functions to handle or manipulate the number  The function also handles normal numbers  so that a number that is suspected to become in an  e  notation can be passed to the function for fixing  The function should work with different locale decimal points  94 test cases are provided  For large e-notation numbers pass the number as a string  Examples  eToNumber  quot 123456789123456789 111122223333444455556666777788889999e 50 quot       output   quot 12345678912345678911112222333344445555666677778888999900000000000000 quot   eToNumber  quot 123 456123456789123456895e-80 quot       output   quot 0 00000000000000000000000000000000000000000000000000000000000000000000000000000123456123456789123456895 quot   eToNumber  quot 123456789123456789 111122223333444455556666777788889999e-50 quot       output   quot 0 00000000000000000000000000000000123456789123456789111122223333444455556666777788889999 quot   Valid e-notation numbers in Javascript include the following  123e1      gt  1230 123E1      gt  1230 123e 1     gt  1230 123 e 1    gt  1230 123e-1     gt  12 3 0 1e-1     gt  0 01  1e-1      gt  0 01 -123e1     gt  -1230   x000D   x000D                                                                         Converts e-Notation Numbers to Plain Numbers                                                                         function eToNumber number      version  1 00     param    e nottation Number  valid Number in exponent format              pass number as a string for very large  e  numbers or with large fractions              none  e  number returned as is       return   string   a decimal number string      author  Mohsen Alyafei     date    17 Jan 2020    Note  No check is made for NaN or undefined input numbers                                                                         function eToNumber num      let sign          num        charAt 0      -   amp  amp   num   num substring 1   sign    -      let arr   num split   e  ig     if  arr length  lt  2  return sign   num    let dot     1  toLocaleString   substr 1  1   n   arr 0   exp    arr 1     let w    n   n replace   0         replace dot           pos   n split dot  1    n indexOf dot    exp   w length   exp      L   pos - w length  s        BigInt w     w   exp  gt   0    L  gt   0   s    0  repeat L    r       pos  lt   0    0    dot    0  repeat Math abs pos     s   r       if    w  w   0  return sign   w    function r    return w replace new RegExp        pos            1  dot  2                                                                                                                                             Test Cases                                                    let r   0     test tracker r    test 1   123456789123456789 111122223333444455556666777788889999e 50    12345678912345678911112222333344445555666677778888999900000000000000    r    test 2   123456789123456789 111122223333444455556666777788889999e-50    0 00000000000000000000000000000000123456789123456789111122223333444455556666777788889999    r    test 3   123456789e3    123456789000    r    test 4   123456789e1    1234567890    r    test 5   1 123e3    1123    r    test 6   12 123e3    12123    r    test 7   1 1234e1    11 234    r    test 8   1 1234e4    11234    r    test 9   1 1234e5    112340    r    test 10   123e 0    123    r    test 11   123E0    123                                      r    test 12   123e-1    12 3    r    test 13   123e-2    1 23    r    test 14   123e-3    0 123    r    test 15   123e-4    0 0123    r    test 16   123e-2    1 23    r    test 17   12345 678e-1    1234 5678    r    test 18   12345 678e-5    0 12345678    r    test 19   12345 678e-6    0 012345678    r    test 20   123 4e-2    1 234    r    test 21   123 4e-3    0 1234    r    test 22   123 4e-4    0 01234    r    test 23   -123e 0    -123    r    test 24   123e1    1230    r    test 25   123e3    123000    r    test 26  -1e33   -1000000000000000000000000000000000    r    test 27   123e 3    123000    r    test 28   123E 7    1230000000    r    test 29   -123 456e 1    -1234 56    r    test 30   -1 0e 1    -10    r    test 31   -1 e 1    -10    r    test 32   -1e 1    -10    r    test 34   -0    -0    r    test 37   0e0    0    r    test 38   123 456e 4    1234560    r    test 39   123E-0    123    r    test 40   123 456e 50    12345600000000000000000000000000000000000000000000000     r    test 41   123e-0    123    r    test 42   123e-1    12 3    r    test 43   123e-3    0 123    r    test 44   123 456E-1    12 3456    r    test 45   123 456123456789123456895e-80    0 00000000000000000000000000000000000000000000000000000000000000000000000000000123456123456789123456895    r    test 46   -123 456e-50    -0 00000000000000000000000000000000000000000000000123456     r    test 47   -0e 1    -0    r    test 48   0e 1    0    r    test 49   0 1e 1    1    r    test 50   -0 01e 1    -0 1    r    test 51   0 01e 1    0 1    r    test 52   -123e-7    -0 0000123    r    test 53   123 456e-4    0 0123456     r    test 54   1 e-5    0 00001       handle missing base fractional part r    test 55    123e3    123       handle missing base whole part     The Electron s Mass  r    test 56   9 10938356e-31    0 000000000000000000000000000000910938356       The Earth s Mass  r    test 57   5 9724e 24    5972400000000000000000000       Planck constant  r    test 58   6 62607015e-34    0 000000000000000000000000000000000662607015     r    test 59   0 000e3    0    r    test 60   0 000000000000000e3    0    r    test 61   -0 0001e 9    -100000    r    test 62   -0 0e1    -0    r    test 63   -0 0000e1    -0      r    test 64   1 2000e0    1 2000    r    test 65   1 2000e-0    1 2000    r    test 66   1 2000e 0    1 2000    r    test 67   1 2000e 10    12000000000    r    test 68   1 12356789445566771234e2    112 356789445566771234        ------------- testing for Non e-Notation Numbers ------------- r    test 69   12345 7898    12345 7898      no exponent r    test 70  12345 7898   12345 7898      no exponent r    test 71  0 00000000000001   0 00000000000001      from 1e-14 r    test 72  0 0000000000001   0 0000000000001      from 1e-13 r    test 73  0 000000000001   0 000000000001      from 1e-12 r    test 74  0 00000000001   0 00000000001      from 1e-11 r    test 75  0 0000000001   0 0000000001      from 1e-10 r    test 76  0 000000001   0 000000001      from 1e-9 r    test 77  0 00000001   0 00000001      from 1e-8 r    test 78  0 0000001   0 0000001      from 1e-7 r    test 79  1e-7   0 0000001      from 1e-7 r    test 80  -0 0000001   -0 0000001      from 1e-7 r    test 81  0 0000005   0 0000005      from 1e-7 r    test 82  0 1000005   0 1000005      from 1e-7 r    test 83  1e-6   0 000001      from 1e-6  r    test 84  0 000001   0 000001       from 1e-6 r    test 85  0 00001   0 00001       from 1e-5 r    test 86  0 0001   0 0001       from 1e-4 r    test 87  0 001   0 001       from 1e-3 r    test 88  0 01   0 01       from 1e-2 r    test 89  0 1   0 1      from 1e-1 r    test 90  -0 0000000000000345   -0 0000000000000345       from -3 45e-14 r    test 91  -0   0    r    test 92   -0    -0    r    test 93 2e64  20000000000000000000000000000000000000000000000000000000000000000    r    test 94  2830869077153280552556547081187254342445169156730   2830869077153280552556547081187254342445169156730     if  r    0  console log  All 94 tests passed                                                                        Test function                                                    function test testNumber  n1  should      let result   eToNumber n1     if  result     should        console log  Test   testNumber  Failed  Output    result  n             Should be    should         return 1        x000D   x000D   x000D

User · Answer

Currently there is no native function to dissolve scientific notation  However  for this purpose you must write your own functionality   Here is my   function dissolveExponentialNotation number        if  Number isFinite number     return undefined         let text   number toString        let items   text split  e         if items length    1    return text         let significandText   items 0       let exponent   parseInt items 1         let characters   Array from significandText       let minus   characters 0      -       if minus    characters splice 0  1         let indexDot   characters reduce  accumulator  character  index    gt                if  accumulator found    if character           accumulator found   true    else   accumulator index                return accumulator           index  0  found  false    index       characters splice indexDot  1        indexDot    exponent       if indexDot  gt   0  amp  amp  indexDot  lt  characters length - 1                characters splice indexDot  0                  else if indexDot  lt  0                characters unshift  0     0  repeat -indexDot              else               characters push  0  repeat indexDot - characters length               return  minus    -          characters join

User · Answer

The answers of others do not give you the exact number   This function calculates the desired number accurately and returns it in the string to prevent it from being changed by javascript   If you need a numerical result  just multiply the result of the function in number one   function toNonExponential value           if value is not a number try to convert it to number     if  typeof value      number             value   parseFloat value               after convert  if value is not a number return empty string         if  isNaN value                 return                          var sign      var e          if value is negative  save  -  in sign variable and calculate the absolute value     if  value  lt  0            sign    -           value   Math abs value             else           sign                     if value is between 0 and 1     if  value  lt  1 0               get e value         e   parseInt value toString   split  e-   1                if value is exponential convert it to non exponential         if  e                value    Math pow 10  e - 1               value    0      new Array e   join  0     value toString   substring 2                       else              get e value         e   parseInt value toString   split  e    1                if value is exponential convert it to non exponential         if  e                value    Math pow 10  e               value     new Array e   1   join  0                            if value has negative sign  add to it     return sign   value

User · Answer

For small number  and you know how many decimals you want  you can use toFixed and then use a regexp to remove the trailing zeros   Number 1e-7  toFixed 8  replace     0          0 000

User · Answer

If you are just doing it for display  you can build an array from the digits before they re rounded   var num   Math pow 2  100   var reconstruct       while num  gt  0        reconstruct unshift num   10       num   Math floor num   10     console log reconstruct join

User · Answer

You can use from-exponential module  It is lightweight and fully tested   import fromExponential from  from-exponential    fromExponential 1 123e-10        gt   0 0000000001123

User · Answer

I know it s many years later  but I had been working on a similar issue recently and I wanted to post my solution   The currently accepted answer pads out the exponent part with 0 s  and mine attempts to find the exact answer  although in general it isn t perfectly accurate for very large numbers because of JS s limit in floating point precision   This does work for Math pow 2  100   returning the correct value of 1267650600228229401496703205376    x000D   x000D  function toFixed x    x000D    var result       x000D    var xStr   x toString 10   x000D    var digitCount   xStr indexOf  e       -1   xStr length    parseInt xStr substr xStr indexOf  e     1     1   x000D     x000D    for  var i   1  i  lt   digitCount  i      x000D      var mod    x   Math pow 10  i   toString 10   x000D      var exponent    mod indexOf  e       -1    0   parseInt mod substr mod indexOf  e   1    x000D      if   exponent     0  amp  amp  mod length     i      exponent  gt  0  amp  amp  exponent     i-1     x000D        result    0    result  x000D        x000D      else   x000D        result   mod charAt 0    result  x000D        x000D      x000D    return result  x000D    x000D   x000D  console log toFixed Math pow 2 100        1267650600228229401496703205376 x000D   x000D   x000D

User · Answer

I had the same issue with oracle returning scientic notation  but I needed the actual number for a url   I just used a PHP trick by subtracting zero  and I get the correct number   for example 5 4987E7 is the val   newval   val - 0    newval now equals 54987000

User · Answer

Use  toPrecision   toFixed  etc  You can count the number of digits in your number by converting it to a string with   toString then looking at its  length

User · Answer

You can also use YourJS fullNumber   For instance YourJS fullNumber Number MAX VALUE  results in the following  179769313486231570000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000  It also works for really small numbers   YourJS fullNumber Number MIN VALUE  returns this  0 000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000005  It is important to note that this function will always return finite numbers as strings but will return non-finite numbers  eg  NaN or Infinity  as undefined   You can test it out in the YourJS Console here

User · Answer

The following solution bypasses the automatic exponentional formatting for very big and very small numbers  This is outis s solution with a bugfix  It was not working for very small negative numbers    x000D   x000D  function numberToString num  x000D    x000D      let numStr   String num   x000D   x000D      if  Math abs num   lt  1 0  x000D        x000D          let e   parseInt num toString   split  e-   1    x000D          if  e  x000D            x000D              let negative   num  lt  0  x000D              if  negative  num    -1 x000D              num    Math pow 10  e - 1   x000D              numStr    0      new Array e   join  0     num toString   substring 2   x000D              if  negative  numStr    -    numStr  x000D            x000D        x000D      else x000D        x000D          let e   parseInt num toString   split      1    x000D          if  e  gt  20  x000D            x000D              e -  20  x000D              num    Math pow 10  e   x000D              numStr   num toString      new Array e   1   join  0    x000D            x000D        x000D   x000D      return numStr  x000D    x000D   x000D     testing     x000D  console log numberToString  0 0000000000000000001    x000D  console log numberToString -0 0000000000000000001    x000D  console log numberToString  314564649798762418795    x000D  console log numberToString -314564649798762418795    x000D   x000D   x000D

User · Answer

I think there may be several similar answers  but here s a thing I came up with     If you re gonna tell me not to use  with  I understand  just     it has no other purpose     andthe code actually looks neater     with  it but I will edit the answer if anyone insists var commas   false   function digit number1  index1  base1        with  Math            return floor number1 pow base1  index1   base1           function digits number1  base1        with  Math            o               l   floor log10 number1  log10 base1            for  var index1   0  index1  lt  l 1  index1                  o   digit number1  index1  base1    o              if  commas  amp  amp  i 3  2  amp  amp  i lt l                    o         o                                  return o              Test - this is the limit of accurate digits I think console log 1234567890123450     Note  this is only as accurate as the javascript math functions and has problems when using log instead of log10 on the line before the for loop  it will write 1000 in base-10 as 000 so I changed it to log10 because people will mostly be using base-10 anyways   This may not be a very accurate solution but I m proud to say it can successfully translate numbers across bases and comes with an option for commas

User · Answer

Here is my short variant of Number prototype toFixed method that works with any number    x000D   x000D  Number prototype toFixedSpecial   function n    x000D    var str   this toFixed n   x000D    if  str indexOf  e        -1  x000D      return str  x000D   x000D       if number is in scientific notation  pick  b ase and  p ower x000D    str   str replace          split  e    reduce function p  b    x000D      return p   Array b - p length   2  join 0   x000D        x000D     x000D    if  n  gt  0  x000D      str          Array n   1  join 0   x000D     x000D    return str  x000D     x000D   x000D  console log  1e21 toFixedSpecial 2               1000000000000000000000 00  x000D  console log  2 1e24 toFixedSpecial 0             2100000000000000000000000  x000D  console log  1234567  toFixedSpecial 1           1234567 0  x000D  console log  1234567 89 toFixedSpecial 3         1234567 890  x000D   x000D   x000D

User · Answer

Your question   number  0x68656c6c6f206f72656f display 4 9299704811152646e 23   You can use this  https   github com MikeMcl bignumber js     A JavaScript library for arbitrary-precision decimal and non-decimal arithmetic    like this   let ten  new BigNumber  0x68656c6c6f206f72656f  16   console log ten toString 10    display 492997048111526447310191

[javascript] How to avoid scientific notation for large numbers in JavaScript?

Examples related to javascript