What does int 0x80 mean in assembly code

Question

Can someone explain what the following assembly code does    int 0x80

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int is nothing but an interruption i e the processor will put its current execution to hold  0x80 is nothing but a system call or the kernel call  i e the system function will be executed  To be specific 0x80 represents rt sigtimedwait init module restart sys it varies from architecture to architecture  For more details refer https   chromium googlesource com chromiumos docs   master constants syscalls md

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Keep in mind that 0x80   80h   128 You can see here that INT is just one of the many instructions  actually the Assembly Language representation  or should I say  mnemonic   of it  that exists in the x86 instruction set  You can also find more information about this instruction in Intel s own manual found here  To summarize from the PDF   INT n INTO INT 3   Call to Interrupt Procedure The INT n instruction generates a call to the interrupt or exception handler specified with the destination operand  The destination operand specifies a vector from 0 to 255  encoded as an 8-bit unsigned intermediate value  The INT n instruction is the general mnemonic for executing a software-generated call to an interrupt handler   As you can see 0x80 is the destination operand in your question  At this point the CPU knows that it should execute some code that resides in the Kernel  but what code  That is determined by the Interrupt Vector in Linux  One of the most useful DOS software interrupts was interrupt 0x21  By calling it with different parameters in the registers  mostly ah and al  you could access various IO operations  string output and more  Most Unix systems and derivatives do not use software interrupts  with the exception of interrupt 0x80  used to make system calls  This is accomplished by entering a 32-bit value corresponding to a kernel function into the EAX register of the processor and then executing INT 0x80  Take a look at this please where other available values in the interrupt handler tables are shown   As you can see the table points the CPU to execute a system call  You can find the Linux System Call table here  So by moving the value 0x1 to EAX register and calling the INT 0x80 in your program  you can make the process go execute the code in Kernel which will stop  exit  the current running process  on Linux  x86 Intel CPU   A hardware interrupt must not be confused with a software interrupt  Here is a very good answer on this regard  This also is good source

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It tells the cpu to activate interrupt vector 0x80  which on Linux OSes is the system-call interrupt  used to invoke system functions like open   for files  et cetera

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The  quot int quot  instruction causes an interrupt  What s an interrupt  Simple Answer  An interrupt  put simply  is an event that interrupts the CPU  and tells it to run a specific task  Detailed Answer  The CPU has a table of Interrupt Service Routines  or ISRs  stored in memory  In Real  16-bit  Mode  this is stored as the IVT  or Interrupt Vector Table  The IVT is typically located at 0x0000 0x0000  physical address 0x00000   and it is a series of segment-offset addresses that point to the ISRs  The OS may replace the pre-existing IVT entries with its own ISRs   Note  The IVT s size is fixed at 1024  0x400  bytes   In Protected  32-bit  Mode  the CPU uses an IDT  The IDT is a variable-length structure that consists of descriptors  otherwise known as gates   which tell the CPU about the interrupt handlers  The structure of these descriptors is much more complex than the IVT s simple segment-offset entries  here it is  bytes 0  1  Lower 16 bits of the ISR s address  bytes 2  3  A code segment selector  in the GDT LDT  byte 4  Zero  byte 5  A type field consisting of several bitfields      bit 0   P  Present   0 for unused interrupts  1 for used interrupts       bits 1  2  DPL  Descriptor Privilege Level   The privilege level the descriptor  bytes 2  3  must have      bit 3  S  Storage Segment   Is 0 for interrupt and trap gates  Otherwise  is one       bits 4  5  6  7  GateType          0101  32 bit task gate         0110  16-bit interrupt gate         0111  16-bit trap gate         1110  32-bit interrupt gate         1111  32-bit trap gate     The IDT may be of variable size  but it must be sequential  i e  if you declare your IDT to be from 0x00 to 0x50  you must have every interrupt from 0x00 to 0x50  The OS does not necessarily use all of them  so the Present bit allows the CPU to properly handle interrupts the OS does not intend to handle  When an interrupt occurs  either by an external trigger  e g  a hardware device  in an IRQ  or by the int instruction from a program   the CPU pushes EFLAGS  then CS  and then EIP   These are automatically restored by iret  the interrupt return instruction   The OS usually stores more information about the state of the machine  handles the interrupt  restores the machine state  and continues on  In many  NIX OSes  including Linux   system calls are interrupt based  The program puts the arguments to the system call in the registers  EAX  EBX  ECX  EDX  etc     and calls interrupt 0x80  The kernel has already set the IDT to contain an interrupt handler on 0x80  which is called when it receives interrupt 0x80  The kernel then reads the arguments and invokes a kernel function accordingly  It may store a return in EAX EBX  System calls have largely been replaced by the sysenter and sysexit  or syscall and sysret on AMD  instructions  which allow for faster entry into ring 0  This interrupt could have a different meaning in a different OS  Be sure to check its documentation

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Minimal runnable Linux system call example  Linux sets up the interrupt handler for 0x80 such that it implements system calls  a way for userland programs to communicate with the kernel    data     s           ascii  hello world n          len     - s  text      global  start      start           movl  4   eax      write system call number            movl  1   ebx      stdout            movl  s   ecx      the data to print            movl  len   edx    length of the buffer            int  0x80          movl  1   eax      exit system call number            movl  0   ebx      exit status            int  0x80   Compile and run with   as -o main o main S ld -o main out main o   main out   Outcome  the program prints to stdout   hello world   and exits cleanly   You cannot set your own interrupt handlers directly from userland because you only have ring 3 and Linux prevents you from doing so   GitHub upstream  Tested on Ubuntu 16 04   Better alternatives  int 0x80 has been superseded by better alternatives for making system calls  first sysenter  then VDSO   x86 64 has a new syscall instruction   See also  What is better  quot int 0x80 quot  or  quot syscall quot    Minimal 16-bit example  First learn how to create a minimal bootloader OS and run it on QEMU and real hardware as I ve explained here  https   stackoverflow com a 32483545 895245  Now you can run in 16-bit real mode       movw  handler0  0x00     mov  cs  0x02     movw  handler1  0x04     mov  cs  0x06     int  0     int  1     hlt handler0         Do 0         iret handler1         Do 1         iret   This would do in order    Do 0  Do 1  hlt  stop executing   Note how the processor looks for the first handler at address 0  and the second one at 4  that is a table of handlers called the IVT  and each entry has 4 bytes   Minimal example that does some IO to make handlers visible   Minimal protected mode example  Modern operating systems run in the so called protected mode   The handling has more options in this mode  so it is more complex  but the spirit is the same   The key step is using the LGDT and LIDT instructions  which point the address of an in-memory data structure  the Interrupt Descriptor Table  that describes the handlers   Minimal example

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As mentioned  it causes control to jump to interrupt vector 0x80   In practice what this means  at least under Linux  is that a system call is invoked  the exact system call and arguments are defined by the contents of the registers   For example  exit   can be invoked by setting  eax to 1 followed by  int 0x80

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int means interrupt  and the number 0x80 is the interrupt number  An interrupt transfers the program flow to whomever is handling that interrupt  which is interrupt 0x80 in this case   In Linux  0x80 interrupt handler is the kernel  and is used to make system calls to the kernel by other programs   The kernel is notified about which system call the program wants to make  by examining the value in the register  eax  AT amp T syntax  and EAX in Intel syntax   Each system call have different requirements about the use of the other registers  For example  a value of 1 in  eax means a system call of exit    and the value in  ebx holds the value of the status code for exit

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It passes control to interrupt vector 0x80  See http   en wikipedia org wiki Interrupt vector  On Linux  have a look at this  it was used to handle system call   Of course on another OS this could mean something totally different

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int 0x80 is the assembly language   instruction that is used to invoke   system calls in Linux on x86  i e     Intel-compatible  processors    http   www linfo org int 0x80 html

[assembly] What does "int 0x80" mean in assembly code?

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