For ios6 using autolayout I had to add a little bit of code to remove the constraints too.
NSMutableArray * constraints_to_remove = [ @[] mutableCopy] ;
for( NSLayoutConstraint * constraint in tagview.constraints) {
if( [tagview.subviews containsObject:constraint.firstItem] ||
[tagview.subviews containsObject:constraint.secondItem] ) {
[constraints_to_remove addObject:constraint];
}
}
[tagview removeConstraints:constraints_to_remove];
[ [tagview subviews] makeObjectsPerformSelector:@selector(removeFromSuperview)];
I'm sure theres a neater way to do this, but it worked for me. In my case I could not use a direct [tagview removeConstraints:tagview.constraints]
as there were constraints set in XCode that were getting cleared.
Using Swift UIView
extension:
extension UIView {
func removeAllSubviews() {
for subview in subviews {
subview.removeFromSuperview()
}
}
}
Get all the subviews from your root controller and send each a removeFromSuperview:
NSArray *viewsToRemove = [self.view subviews];
for (UIView *v in viewsToRemove) {
[v removeFromSuperview];
}
In order to remove all subviews from superviews:
NSArray *oSubView = [self subviews];
for(int iCount = 0; iCount < [oSubView count]; iCount++)
{
id object = [oSubView objectAtIndex:iCount];
[object removeFromSuperview];
iCount--;
}
view.subviews.forEach { $0.removeFromSuperview() }
In monotouch / xamarin.ios this worked for me:
SomeParentUiView.Subviews.All(x => x.RemoveFromSuperview);
Try this way swift 2.0
view.subviews.forEach { $0.removeFromSuperview() }
In objective-C, go ahead and create a category method off of the UIView class.
- (void)removeAllSubviews
{
for (UIView *subview in self.subviews)
[subview removeFromSuperview];
}
Use the Following code to remove all subviews.
for (UIView *view in [self.view subviews])
{
[view removeFromSuperview];
}
In order to remove all subviews Syntax :
- (void)makeObjectsPerformSelector:(SEL)aSelector;
Usage :
[self.View.subviews makeObjectsPerformSelector:@selector(removeFromSuperview)];
This method is present in NSArray.h file and uses NSArray(NSExtendedArray) interface
This does only apply to OSX since in iOS a copy of the array is kept
When removing all the subviews, it is a good idea to start deleting at the end of the array and keep deleting until you reach the beginning. This can be accomplished with this two lines of code:
for (int i=mySuperView.subviews.count-1; i>=0; i--)
[[mySuperView.subviews objectAtIndex:i] removeFromSuperview];
SWIFT 1.2
for var i=mySuperView.subviews.count-1; i>=0; i-- {
mySuperView.subviews[i].removeFromSuperview();
}
or (less efficient, but more readable)
for subview in mySuperView.subviews.reverse() {
subview.removeFromSuperview()
}
NOTE
You should NOT remove the subviews in normal order, since it may cause a crash if a UIView instance is deleted before the removeFromSuperview
message has been sent to all objects of the array. (Obviously, deleting the last element would not cause a crash)
Therefore, the code
[[someUIView subviews] makeObjectsPerformSelector:@selector(removeFromSuperview)];
should NOT be used.
Quote from Apple documentation about makeObjectsPerformSelector:
Sends to each object in the array the message identified by a given selector, starting with the first object and continuing through the array to the last object.
(which would be the wrong direction for this purpose)
In Swift you can use a functional approach like this:
view.subviews.forEach { $0.removeFromSuperview() }
As a comparison, the imperative approach would look like this:
for subview in view.subviews {
subview.removeFromSuperview()
}
These code snippets only work in iOS / tvOS though, things are a little different on macOS.
If you're using Swift, it's as simple as:
subviews.map { $0.removeFromSuperview }
It's similar in philosophy to the makeObjectsPerformSelector
approach, however with a little more type safety.
If you want to remove all the subviews on your UIView (here yourView
), then write this code at your button click:
[[yourView subviews] makeObjectsPerformSelector: @selector(removeFromSuperview)];
Source: Stackoverflow.com