How to get domain URL and application name

Question

Here s the scenario   My Java web application has following path  https   www mywebsite com 9443 MyWebApp   Let s say there is a JSP file  https   www mywebsite com 9443 MyWebApp protected index jsp   and I need to retrieve   https   www mywebsite com 9443 MyWebApp    within this JSP file   Of course  there is rather a lazy and silly way of just getting the URL and then re-tracing the path back   But is there a programatic way of doing this  Specifically  I think I can get the domain   port  but how do I actually retrieve the application name  MyWebApp

User · Answer

I would strongly suggest you to read through the docs  for similar methods  If you are interested in context path  have a look here  ServletContext getContextPath

User · Answer

The following code might be useful for web application using JavaScript   var newURL   window location protocol           window location host        window location pathname   newURL   newURL substring 0 newURL indexOf

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If you are being passed a url as a String and want to extract the context root of that application  you can use this regex to extract it   It will work for full urls or relative urls that begin with the context root   url replaceAll                                            2 3

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The application name come from getContextPath   I find this graphic from Agile Software Craftsmanship HttpServletRequest Path Decoding  sorts out all the different methods that are available

User · Answer

The web application name  actually the context path  is available by calling HttpServletrequest getContextPath    and thus NOT getServletPath   as one suggested before   You can retrieve this in JSP by   pageContext request contextPath      lt p gt The context path is    pageContext request contextPath   lt  p gt    If you intend to use this for all relative paths in your JSP page  which would make this question more sense   then you can make use of the HTML  lt base gt  tag    lt   taglib prefix  c  uri  http   java sun com jsp jstl core    gt   lt   taglib prefix  fn  uri  http   java sun com jsp jstl functions    gt   lt c set var  req  value    pageContext request     gt   lt c set var  url  gt   req requestURL  lt  c set gt   lt c set var  uri  value    req requestURI     gt    lt  doctype html gt   lt html lang  en  gt       lt head gt           lt title gt SO question 2204870 lt  title gt           lt base href    fn substring url  0  fn length url  - fn length uri     req contextPath    gt           lt script src  js global js  gt  lt  script gt           lt link rel  stylesheet  href  css global css  gt       lt  head gt       lt body gt           lt ul gt               lt li gt  lt a href  home jsp  gt Home lt  a gt  lt  li gt               lt li gt  lt a href  faq jsp  gt FAQ lt  a gt  lt  li gt               lt li gt  lt a href  contact jsp  gt Contact lt  a gt  lt  li gt           lt  ul gt       lt  body gt   lt  html gt    All links in the page will then automagically be relative to the  lt base gt  so that you don t need to copypaste the context path everywhere  Note that when relative links start with a    then they will not be relative to the  lt base gt  anymore  but to the domain root instead

User · Answer

Take a look at the documentation for HttpServletRequest  In order to build the URL in your example you will need to use     getScheme   getServerName   getServerPort   getContextPath     Here is a method that will return your example   public static String getURLWithContextPath HttpServletRequest request       return request getScheme             request getServerName           request getServerPort     request getContextPath

[jsp] How to get domain URL and application name?

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