HttpServletRequest to complete URL

Question

I have an HttpServletRequest object   How do I get the complete and exact URL that caused this call to arrive at my servlet   Or at least as accurately as possible  as there are perhaps things that can be regenerated  the order of the parameters  perhaps

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I use this method   public static String getURL HttpServletRequest req         String scheme   req getScheme                   http     String serverName   req getServerName           hostname com     int serverPort   req getServerPort              80     String contextPath   req getContextPath          mywebapp     String servletPath   req getServletPath          servlet MyServlet     String pathInfo   req getPathInfo                a b c 123     String queryString   req getQueryString                d 789         Reconstruct original requesting URL     StringBuilder url   new StringBuilder        url append scheme  append        append serverName        if  serverPort    80  amp  amp  serverPort    443            url append      append serverPort              url append contextPath  append servletPath        if  pathInfo    null            url append pathInfo             if  queryString    null            url append      append queryString             return url toString

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The HttpServletRequest has the following methods    getRequestURL   - returns the part of the full URL before query string separator character   getQueryString   - returns the part of the full URL after query string separator character     So  to get the full URL  just do   public static String getFullURL HttpServletRequest request        StringBuilder requestURL   new StringBuilder request getRequestURL   toString         String queryString   request getQueryString         if  queryString    null            return requestURL toString          else           return requestURL append      append queryString  toString

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In a Spring project you can use   UriComponentsBuilder fromHttpRequest new ServletServerHttpRequest request   build   toUriString

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You can use filter     Override     public void doFilter ServletRequest arg0  ServletResponse arg1  FilterChain arg2  throws IOException  ServletException               HttpServletRequest test1      HttpServletRequest  arg0            test1 getRequestURL     it gives  http   localhost 8081 applicationName menu index action          test1 getRequestURI     it gives applicationName menu index action          String pathname   test1 getServletPath     it gives   menu index action           if pathname equals    menu index action                  arg2 doFilter arg0  arg1      call to urs servlet or frameowrk managed controller method                  in resposne             HttpServletResponse httpResp    HttpServletResponse  arg1             RequestDispatcher rd   arg0 getRequestDispatcher  another jsp                    rd forward arg0  arg1                donot forget to put   lt dispatcher gt FORWARD lt  dispatcher gt  in filter mapping in web xml

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HttpUtil being deprecated  this is the correct method  StringBuffer url   req getRequestURL    String queryString   req getQueryString    if  queryString    null        url append           url append queryString     String requestURL   url toString

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You can write a simple one liner with a ternary and if you make use of the builder pattern of the StringBuffer from  getRequestURL     private String getUrlWithQueryParms final HttpServletRequest request         return request getQueryString      null   request getRequestURL   toString             request getRequestURL   append      append request getQueryString    toString        But that is just syntactic sugar

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Combining the results of getRequestURL   and getQueryString   should get you the desired result

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http   hostname com mywebapp servlet MyServlet a b c 123 d 789  public static String getUrl HttpServletRequest req        String reqUrl   req getRequestURL   toString        String queryString   req getQueryString         d 789     if  queryString    null            reqUrl        queryString            return reqUrl

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Use the following methods on HttpServletRequest object  java lang String getRequestURI   -Returns the part of this request s URL from the protocol name up to the query string in the first line of the HTTP request   java lang StringBuffer getRequestURL    -Reconstructs the URL the client used to make the request   java lang String getQueryString    -Returns the query string that is contained in the request URL after the path

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Somewhat late to the party  but I included this in my MarkUtils-Web library in WebUtils - Checkstyle-approved and JUnit-tested   import javax servlet http HttpServletRequest   public class GetRequestUrl                  lt p gt A faster replacement for   link HttpServletRequest getRequestURL             returns a   link String  instead of a   link StringBuffer  - and internally uses a   link StringBuilder           that also includes the   linkplain HttpServletRequest getQueryString   query string   lt  p gt          lt p gt  lt a href  https   gist github com ziesemer 700376d8da8c60585438           gt https   gist github com ziesemer 700376d8da8c60585438 lt  a gt  lt  p gt          author Mark A  Ziesemer          lt a href  http   www ziesemer com   gt  amp lt www ziesemer com amp gt  lt  a gt              public String getRequestUrl final HttpServletRequest req           final String scheme   req getScheme            final int port   req getServerPort            final StringBuilder url   new StringBuilder 256           url append scheme           url append                 url append req getServerName             if     http  equals scheme   amp  amp   port    0    port    80                        https  equals scheme   amp  amp  port    443                 url append                   url append port                     url append req getRequestURI             final String qs   req getQueryString            if qs    null               url append                   url append qs                     final String result   url toString            return result            Probably the fastest and most robust answer here so far behind Mat Banik s - but even his doesn t account for potential non-standard port configurations with HTTP HTTPS   See also    http   blogger ziesemer com 2017 08 httpservletrequestgetrequesturl html https   gist github com ziesemer 700376d8da8c60585438

[java] HttpServletRequest to complete URL

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