[c++] how do I initialize a float to its max/min value?

How do I hard code an absolute maximum or minimum value for a float or double? I want to search out the max/min of an array by simply iterating through and catching the largest.

There are also positive and negative infinity for floats, should I use those instead? If so, how do I denote that in my code?

There's no real need to initialize to smallest/largest possible to find the smallest/largest in the array:

double largest = smallest = array[0];
for (int i=1; i<array_size; i++) {
    if (array[i] < smallest)
        smallest = array[i];
    if (array[i] > largest0
        largest= array[i];
}

Or, if you're doing it more than once:

#include <utility>

template <class iter>
std::pair<typename iter::value_type, typename iter::value_type> find_extrema(iter begin, iter end) {
    std::pair<typename iter::value_type, typename iter::value_type> ret;
    ret.first = ret.second = *begin;
    while (++begin != end) {
        if (*begin < ret.first)
           ret.first = *begin;
        if (*begin > ret.second)
           ret.second = *begin;
   }
   return ret;
}

The disadvantage of providing sample code -- I see others have already suggested the same idea.

Note that while the standard has a min_element and max_element, using these would require scanning through the data twice, which could be a problem if the array is large at all. Recent standards have addressed this by adding a std::minmax_element, which does the same as the find_extrema above (find both the minimum and maximum elements in a collection in a single pass).

Edit: Addressing the problem of finding the smallest non-zero value in an array of unsigned: observe that unsigned values "wrap around" when they reach an extreme. To find the smallest non-zero value, we can subtract one from each for the comparison. Any zero values will "wrap around" to the largest possible value for the type, but the relationship between other values will be retained. After we're done, we obviously add one back to the value we found.

unsigned int min_nonzero(std::vector<unsigned int> const &values) { 
    if (vector.size() == 0)
        return 0;
    unsigned int temp = values[0]-1;
    for (int i=1; i<values.size(); i++)
        if (values[i]-1 < temp)
            temp = values[i]-1;
    return temp+1;
}

Note this still uses the first element for the initial value, but we still don't need any "special case" code -- since that will wrap around to the largest possible value, any non-zero value will compare as being smaller. The result will be the smallest nonzero value, or 0 if and only if the vector contained no non-zero values.

May I suggest that you initialize your "max and min so far" variables not to infinity, but to the first number in the array?

You can either use -FLT_MAX (or -DBL_MAX) for the maximum magnitude negative number and FLT_MAX (or DBL_MAX) for positive. This gives you the range of possible float (or double) values.

You probably don't want to use FLT_MIN; it corresponds to the smallest magnitude positive number that can be represented with a float, not the most negative value representable with a float.

FLT_MIN and FLT_MAX correspond to std::numeric_limits<float>::min() and std::numeric_limits<float>::max().

To manually find the minimum of an array you don't need to know the minimum value of float:

float myFloats[];
...
float minimum = myFloats[0];
for (int i = 0; i < myFloatsSize; ++i)
{
  if (myFloats[i] < minimum)
  {
    minimum = myFloats[i];
  }
}

And similar code for the maximum value.