To add on to the other answers here, if you would like to create a new object of a third different type with a where clause (e.g. one that is not your Entity Framework object) you can do this:
public IEnumerable<ThirdNonEntityClass> demoMethod(IEnumerable<int> property1Values)
{
using(var entityFrameworkObjectContext = new EntityFrameworkObjectContext )
{
var result = entityFrameworkObjectContext.SomeClass
.Join(entityFrameworkObjectContext.SomeOtherClass,
sc => sc.property1,
soc => soc.property2,
(sc, soc) => new {sc, soc})
.Where(s => propertyValues.Any(pvals => pvals == es.sc.property1)
.Select(s => new ThirdNonEntityClass
{
dataValue1 = s.sc.dataValueA,
dataValue2 = s.soc.dataValueB
})
.ToList();
}
return result;
}
Pay special attention to the intermediate object that is created in the Where and Select clauses.
Note that here we also look for any joined objects that have a property1 that matches one of the ones in the input list.
I know this is a bit more complex than what the original asker was looking for, but hopefully it will help someone.