C program converts fahrenheit to celsius

Question

Can someone help me understand why this gives an output of 0     include  lt iostream gt                          using namespace std                          int main                                        float celsius                               float fahrenheit       cout  lt  lt   Enter Celsius temperature          cin  gt  gt  celsius      fahrenheit    5 9     celsius   32       cout  lt  lt   Fahrenheit      lt  lt  fahrenheit  lt  lt  endl       return 0

User · Answer

In C    5 9 computes the result as an integer as both the operands are integers  You need to give an hint to the compiler that you want the result as a float double  You can do it by explictly casting one of the operands like   double 5  9   EDIT Since it is tagged C    you can do the casting bit more elegantly using the static cast  For example  static cast lt double gt  5  9  Although in this particular case you can directly use 5 0 9 to get the desired result  the casting will be helpful when you have variables instead of constant values such as 5

User · Answer

It is the simplest one I could come up with  so wanted to share here     include lt iostream h gt   include lt conio h gt  void main       clear the screen  clrscr      declare variable type float float cel  fah    Input the Temperature in given unit save them in    cel    cout lt  lt    Enter the Temperature in Celsius    lt  lt endl  cin gt  gt cel    convert and save it in    fah    fah 1 8 cel 32 0    show the output    fah    cout lt  lt    Temperature in Fahrenheit is     lt  lt fah    get character getch        Source  Celsius to Fahrenheit

User · Answer

Best way would be    include  lt iostream gt                          using namespace std                          int main                                        float celsius                               float fahrenheit       cout  lt  lt   Enter Celsius temperature          cin  gt  gt  celsius      fahrenheit    celsius   1 8    32    removing division for the confusion     cout  lt  lt   Fahrenheit      lt  lt  fahrenheit  lt  lt  endl       return 0

User · Answer

The answer has already been found although I would also like to share my answer    int main void    using namespace std   short tempC  cout  lt  lt   Please enter a Celsius value     cin  gt  gt  tempC  double tempF   convert tempC   cout  lt  lt  tempC  lt  lt    degrees Celsius is    lt  lt  tempF  lt  lt    degrees Fahrenheit    lt  lt  endl  cin get    cin get    return 0      int convert short nT    return nT   1 8   32      This is a more proper way to do this  however  it is slightly more complex then what you were going for

User · Answer

5 9  will by default be computed as an integer division and will be zero  Try  5 0 9

User · Answer

Fahrenheit to celsius would be  Fahrenheit - 32    5   9

User · Answer

In your code sample you are trying to divide an integer with another integer  This is the cause of all your trouble  Here is an article that might find interesting on that subject   With the notion of integer division you can see right away that this is not what you want in your formula  Instead  you need to use some floating point literals   I am a rather confused by the title of this thread and your code sample  Do you want to convert Celsius degrees to Fahrenheit or do the opposite    I will base my code sample on your own code sample until you give more details on what you want   Here is an example of what you can do     include  lt iostream gt    no need to use the whole std namespace    use what you need                            using std  cout  using std  cin  using std  endl                         int main               Variables                                float celsius       represents the temperature in Celsius degrees           fahrenheit    represents the converted temperature in Fahrenheit degrees        Ask for the temperature in Celsius degrees     cout  lt  lt   Enter Celsius temperature          cin  gt  gt  celsius         Formula to convert degrees in Celsius to Fahrenheit degrees       Important note  floating point literals need to have the   0       fahrenheit   celsius   9 0 5 0   32 0         Print the converted temperature to the console     cout  lt  lt   Fahrenheit      lt  lt  fahrenheit  lt  lt  endl

User · Answer

Mine worked perfectly      Two common temperature scales are Fahrenheit and Celsius     The boiling point of water is 212   F  and 100   C     The freezing point of water is 32   F  and 0   C     Assuming that the relationship bewtween these two    temperature scales is  F   9 5C 32     Celsius    f-32    5 9                             include  lt iostream gt     cin  cout  using namespace std     System definition of cin and cout commands                          if not  programmer would have to write every                         single line as  std  cout or std  cin  int main       Main function            Declare variables        double c  f       cout  lt  lt    nProgram that changes temperature from Celsius to Fahrenheit  n       cout  lt  lt   Please enter a temperature in Celsius          cin  gt  gt  c      f   c   9   5   32      cout  lt  lt    nA temperature of    lt  lt  c  lt  lt      Celsius  is equivalent to             lt  lt  f  lt  lt      Fahrenheit  n       return 0

[c++] C++ program converts fahrenheit to celsius

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