If they exist in programming),
If I have an HTML form with the following inputs:
<input type="text" />
<input type="password" />
<input type="checkbox" />
I want to apply a style to all inputs that are either type="text" or type="password".
Alternatively, I would settle for all input's where type != "checkbox".
It seems like I to have to do this:
input[type='text'], input[type='password']
{
// my css
}
Isn't there a way to do:
input[type='text',type='password']
{
// my css
}
or
input[type!='checkbox']
{
// my css
}
I had a look around, and it doesn't seem like there is a way to do this with a single CSS selector.
Not a big deal of course, but I'm just a curious cat.
Any ideas?
This question is related to
html
css
css-selectors
CSS3 has a pseudo-class called :not()
input:not([type='checkbox']) {
visibility: hidden;
}<p>If <code>:not()</code> is supported, you'll only see the checkbox.</p>
<ul>
<li>text: (<input type="text">)</li>
<li>password (<input type="password">)</li>
<li>checkbox (<input type="checkbox">)</li>
</ul>As Vincent mentioned, it's possible to string multiple :not()s together:
input:not([type='checkbox']):not([type='submit'])
CSS4, which is supported in many of the latest browser releases, allows multiple selectors in a :not()
input:not([type='checkbox'],[type='submit'])
All modern browsers support the CSS3 syntax. At the time this question was asked, we needed a fall-back for IE7 and IE8. One option was to use a polyfill like IE9.js. Another was to exploit the cascade in CSS:
input {
// styles for most inputs
}
input[type=checkbox] {
// revert back to the original style
}
input.checkbox {
// for completeness, this would have worked even in IE3!
}
input[type='text'], input[type='password']
{
// my css
}
That is the correct way to do it. Sadly CSS is not a programming language.
Source: Stackoverflow.com