in es6 there you can define a module of functions like this
export default {
foo() { console.log('foo') },
bar() { console.log('bar') },
baz() { foo(); bar() }
}
the above seems to be valid code, but if I call baz()
it throws an error:
ReferenceError: foo is not defined
How do you call foo
from another function? in this case baz
Edit
Here's the code that actually doesn't work. I have simplified the code so it's only the core as needed
const tokenManager = {
revokeToken(headers) {
...
},
expireToken(headers) {
...
},
verifyToken(req, res, next) {
jwt.verify(... => {
if (err) {
expireToken(req.headers)
}
})
}
}
export default tokenManager
and the error is
expireToken(req.headers);
^
ReferenceError: expireToken is not defined
Edit 2
I just tried adding tokenManager
before expireToken
and it finally works
This question is related to
javascript
ecmascript-6
tl;dr: baz() { this.foo(); this.bar() }
In ES2015 this construct:
var obj = {
foo() { console.log('foo') }
}
is equal to this ES5 code:
var obj = {
foo : function foo() { console.log('foo') }
}
exports.default = {}
is like creating an object, your default export translates to ES5 code like this:
exports['default'] = {
foo: function foo() {
console.log('foo');
},
bar: function bar() {
console.log('bar');
},
baz: function baz() {
foo();bar();
}
};
now it's kind of obvious (I hope) that baz
tries to call foo
and bar
defined somewhere in the outer scope, which are undefined. But this.foo
and this.bar
will resolve to the keys defined in exports['default']
object. So the default export referencing its own methods shold look like this:
export default {
foo() { console.log('foo') },
bar() { console.log('bar') },
baz() { this.foo(); this.bar() }
}
One alternative is to change up your module. Generally if you are exporting an object with a bunch of functions on it, it's easier to export a bunch of named functions, e.g.
export function foo() { console.log('foo') },
export function bar() { console.log('bar') },
export function baz() { foo(); bar() }
In this case you are export all of the functions with names, so you could do
import * as fns from './foo';
to get an object with properties for each function instead of the import you'd use for your first example:
import fns from './foo';
Source: Stackoverflow.com