let's say I have a method doWork()
. How do I call it from a separate thread (not the main thread).
This question is related to
java
multithreading
In Java 8 you can do this with one line of code.
If your method doesn't take any parameters, you can use a method reference:
new Thread(MyClass::doWork).start();
Otherwise, you can call the method in a lambda expression:
new Thread(() -> doWork(someParam)).start();
Sometime ago, I had written a simple utility class that uses JDK5 executor service and executes specific processes in the background. Since doWork() typically would have a void return value, you may want to use this utility class to execute it in the background.
See this article where I had documented this utility.
To achieve this with RxJava 2.x you can use:
Completable.fromAction(this::dowork).subscribeOn(Schedulers.io().subscribe();
The subscribeOn()
method specifies which scheduler to run the action on - RxJava has several predefined schedulers, including Schedulers.io()
which has a thread pool intended for I/O operations, and Schedulers.computation()
which is intended for CPU intensive operations.
Another quicker option to call things (like DialogBoxes and MessageBoxes and creating separate threads for not-thread safe methods) would be to use the Lamba Expression
new Thread(() -> {
"code here"
}).start();
If you are using at least Java 8 you can use method runAsync
from class CompletableFuture
CompletableFuture.runAsync(() -> {...});
If you need to return a result use supplyAsync
instead
CompletableFuture.supplyAsync(() -> 1);
Thread t1 = new Thread(new Runnable() {
@Override
public void run() {
// code goes here.
}
});
t1.start();
or
new Thread(new Runnable() {
@Override
public void run() {
// code goes here.
}
}).start();
or
new Thread(() -> {
// code goes here.
}).start();
or
Executors.newSingleThreadExecutor().execute(new Runnable() {
@Override
public void run() {
myCustomMethod();
}
});
or
Executors.newCachedThreadPool().execute(new Runnable() {
@Override
public void run() {
myCustomMethod();
}
});
Source: Stackoverflow.com