They often forget that iterator
must convert to const_iterator
but not the other way around. Here is a way to do that:
template<class T, class Tag = void>
class IntrusiveSlistIterator
: public std::iterator<std::forward_iterator_tag, T>
{
typedef SlistNode<Tag> Node;
Node* node_;
public:
IntrusiveSlistIterator(Node* node);
T& operator*() const;
T* operator->() const;
IntrusiveSlistIterator& operator++();
IntrusiveSlistIterator operator++(int);
friend bool operator==(IntrusiveSlistIterator a, IntrusiveSlistIterator b);
friend bool operator!=(IntrusiveSlistIterator a, IntrusiveSlistIterator b);
// one way conversion: iterator -> const_iterator
operator IntrusiveSlistIterator<T const, Tag>() const;
};
In the above notice how IntrusiveSlistIterator<T>
converts to IntrusiveSlistIterator<T const>
. If T
is already const
this conversion never gets used.