[debugging] Chrome: Uncaught SyntaxError: Unexpected end of input

When loading my page in Google Chrome, I get a vague error in the console:

Uncaught SyntaxError: Unexpected end of input

I have no idea what is causing it. How would I go about debugging this error?

JSHint is good at finding the location of missing brackets or bad syntax.

In my case I was adding javascript dynamicly and using double quotes 2 times in string templates so i changed the second to single quotes and the error was gone. I hope it will help some of the people coming here for the same reason.

I get this error when I have ommitted a closing brace character (})in JavaScript code. Check that your braces are properly balanced.

My problem was with Google Chrome cache. I tested this by running my web application on Firefox and I didn't got that error there. So then I decided trying emptying cache of Google Chrome and it worked.

Since it's an async operation the onreadystatechange may happen before the value has loaded in the responseText, try using a window.setTimeout(function () { JSON.parse(xhr.responseText); }, 1000); to see if the error persists? BOL

if you got error at Anchor tag,just replace "Onclick" with "href" or "href" with "Onclick"

In my case, i had low internet speed, when i turn off the other user's internet connection then error has gone, strange

Trying to parse an empty JSON can be the cause of this error.

When you receive a response from the server or whatever, check first if it's not empty. For example:

function parseJSON(response) {
    if (response.status === 204 || response.status === 205) {
        return null;
    }
    return response.json();
}

Then you can fetch with:

fetch(url, options).then(parseJSON); 

In cases where your JavaScript code is minified to a single line, another cause for this error is using // instead of /**/ for your comments.

Bad (comments out everything after // including the closing } for your function)

function example() { //comment console.log('TEST'); }

Good (confines your comment)

function example() { /* comment */ console.log('TEST'); }

Setting the Accept header to application/json in the request worked for me when I faced the same problem.

For the record, for anyone trying to find the various causes for this error. An empty HTML5 data attribute

data-mydata = ''

causes the error too. You should check when the data value is a null string and not include the attribute at all. It goes without saying this is largely relevant to script generated HTML.

Another cause of this error: if your API intentionally responds with no response body, but responds with a 200 OK status code instead of a 204 No Content status code. Some JavaScript libraries may not respond well to unexpected content types when there is no content, so use the correct status code!

Try Firebug for Mozilla - it will show the position of the missing }.

http://getfirebug.com/

I faced similar problem using ui bootstrap directive for angularjs - uib-datepicker, when pressing am/pm toggle.

Error in event handler for (unknown): SyntaxError: Unexpected end of JSON input angular timepicker

Turned out it was because of plugin 'Trans-over' (which translates a word when it is clicked). Maybe my answer will help someone, because I didn't found anything on the internet.

The issue for me was that I was doing $.ajax with dataType: "json" for a POST request that was returning an HTTP 201 (created) and no request body. The fix was to simply remove that key/value.

There will definitely be an open bracket which caused the error.

I'd suggest that you open the page in Firefox, then open Firebug and check the console – it'll show the missing symbol.

Example screenshot:

I had this error and fixed it by adding the guard on readyState and status shown here:

var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
          // Your code here
   }
};

See my case on another similar question:

In my case, I was trying to parse an empty JSON:

JSON.parse(stringifiedJSON);

In other words, what happened was the following:

JSON.parse("");