[ruby-on-rails] Rails Root directory path?

How do I get my Rails app's root directory path?

This question is related to ruby-on-rails

The answer is


module Rails
  def self.root
    File.expand_path("..", __dir__)
  end
end

source: https://github.com/rails/rails/blob/5259062868dcf10fbcf735d6520e6a14e15fdcdb/actionmailer/test/abstract_unit.rb#L12


You can access rails app path using variable RAILS_ROOT.

For example:

render :file => "#{RAILS_ROOT}/public/layouts/mylayout.html.erb"

Simply By writing Rails.root and append anything by Rails.root.join(*%w( app assets)).to_s


You can use:

Rails.root

But to to join the assets you can use:

Rails.root.join(*%w( app assets))

Hopefully this helps you.


For super correctness, you should use:

Rails.root.join('foo','bar')

which will allow your app to work on platforms where / is not the directory separator, should anyone try and run it on one.


Simply by Rails.root or if you want append something we can use it like Rails.root.join('app', 'assets').to_s


In addition to all the other correct answers, since Rails.root is a Pathname object, this won't work:

Rails.root + '/app/assets/...'

You could use something like join

Rails.root.join('app', 'assets')

If you want a string use this:

Rails.root.join('app', 'assets').to_s

In some cases you may want the Rails root without having to load Rails.

For example, you get a quicker feedback cycle when TDD'ing models that do not depend on Rails by requiring spec_helper instead of rails_helper.

# spec/spec_helper.rb

require 'pathname'

rails_root = Pathname.new('..').expand_path(File.dirname(__FILE__))

[
  rails_root.join('app', 'models'),
  # Add your decorators, services, etc.
].each do |path|
  $LOAD_PATH.unshift path.to_s
end

Which allows you to easily load Plain Old Ruby Objects from their spec files.

# spec/models/poro_spec.rb

require 'spec_helper'

require 'poro'

RSpec.describe ...