How would I go about generating a list of sql jobs and their owners? I would also like to be able to generate this list for SSIS packages also.
Thanks
This question is related to
sql-server
There is an easy way to get Jobs' Owners info from multiple instances by PowerShell:
Run the script in your PowerShell ISE:
Loads SQL Powerhell SMO and commands:
Import-Module SQLPS -disablenamechecking
BUild list of Servers manually (this builds an array list):
$SQLServers = "SERVERNAME\INSTANCE01","SERVERNAME\INSTANCE02","SERVERNAME\INSTANCE03";
$SysAdmins = $null;
foreach($SQLSvr in $SQLServers)
{
## - Add Code block:
$MySQL = new-object Microsoft.SqlServer.Management.Smo.Server $SQLSvr;
DIR SQLSERVER:\SQL\$SQLSvr\JobServer\Jobs| FT $SQLSvr, NAME, OWNERLOGINNAME -Auto
## - End of Code block
}
A colleague told me about this stored procedure...
USE msdb
EXEC dbo.sp_help_job
If you don't have access to sysjobs table (someone elses server etc) you might be have or be allowed access to sysjobs_view
SELECT *
from msdb..sysjobs_view s
left join master.sys.syslogins l on s.owner_sid = l.sid
or
SELECT *, SUSER_SNAME(s.owner_sid) AS owner
from msdb..sysjobs_view s
It's better to use SUSER_SNAME() since when there is no corresponding login on the server the join to syslogins will not match
SELECT s.name ,
SUSER_SNAME(s.owner_sid) AS owner
FROM msdb..sysjobs s
ORDER BY name
Source: Stackoverflow.com