How to get the real path of Java application at runtime

Question

I am creating a Java application where I am using log4j  I have given the absolute path of configuration log4j file and also an absolute path of generated log file where this log file are generated   I can get the absolute path of a Java web application at run time via   String prefix    getServletContext   getRealPath         but in the context of a normal Java application  what can we use

User · Answer

The expression  new File      getAbsolutePath      will get you the current working directory associated with the execution of JVM  However  the JVM does provide a wealth of other useful properties via the  System getProperty propertyName      interface  A list of these properties can be found here   These will allow you to reference the current users directory  the temp directory and so on in a platform independent manner

User · Answer

It is better to save files into a sub-directory of user home than wherever the app  might reside     Sun went to considerable effort to ensure that applets and apps  launched using Java Web Start cannot determine the apps  real path   This change broke many apps  I would not be surprised if the changes are extended to other apps

User · Answer

And what about using this getClass   getProtectionDomain   getCodeSource   getLocation

User · Answer

It isn t clear what you re asking for  I don t know what  with respect to the web application we are using  means if getServletContext   getRealPath   isn t the answer  but    The current user s current working directory is given by System getProperty  user dir   The current user s home directory is given by System getProperty  user home   The location of the JAR file from which the current class was loaded is given by this getClass   getProtectionDomain   getCodeSource   getLocation

User · Answer

If you re talking about a web application  you should use the getRealPath from a ServletContext object   Example   public class MyServlet extends Servlet       public void doGet HttpServletRequest req  HttpServletResponse resp                 throws ServletException  IOException           String webAppPath   getServletContext   getRealPath                 Hope this helps

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If you want to use this answer   https   stackoverflow com a 4033033 10560907  You must add import statement like this   import java io File   in very beginning java source code   like this answer  https   stackoverflow com a 43553093 10560907

User · Answer

I use this method to get complete path to jar or exe   File pto   new File YourClass class getProtectionDomain   getCodeSource   getLocation   toURI      pto getAbsolutePath

User · Answer

If you want to get the real path of java web application such as Spring  Servlet   you can get it from Servlet Context object that comes with your HttpServletRequest    GetMapping      public String index ModelMap m  HttpServletRequest request        String realPath   request getServletContext   getRealPath           System out println realPath       return  index

User · Answer

new File      getAbsolutePath

User · Answer

Try   String path   new File      getCanonicalPath

User · Answer

I have a file  cost ini  on the root of my class path  My JAR file is named  cost jar   The following code  If we have a JAR file  takes the directory where the JAR file is  If we have   class files  takes the directory of the root of classes   try         JDK11  replace  UTF-8  with UTF 8 and remove try-catch     String rootPath   decode getSystemResource  cost ini   getPath                replaceAll   cost   jar    cost   ini    file               UTF-8        showMessageDialog null  rootPath   rootpath   WARNING MESSAGE     catch UnsupportedEncodingException e       Path returned from  getPath   has the format  In JAR  file  C  folder1 folder2 cost jar  cost ini In   class   C  folder1 folder2 cost ini  Every use of File  leads on exception  if the application provided in JAR format

User · Answer

return application path         return                                                                                         public static String getApplcatonPath            CodeSource codeSource   MainApp class getProtectionDomain   getCodeSource            File rootPath   null          try               rootPath   new File codeSource getLocation   toURI   getPath               catch  URISyntaxException e                   TODO Auto-generated catch block             e printStackTrace                                 return rootPath getParentFile   getPath           end of getApplcatonPath

User · Answer

Since the application path of a JAR and an application running from inside an IDE differs  I wrote the following code to consistently return the correct current directory   import java io File  import java net URISyntaxException   public class ProgramDirectoryUtilities       private static String getJarName                 return new File ProgramDirectoryUtilities class getProtectionDomain                    getCodeSource                    getLocation                    getPath                     getName               private static boolean runningFromJAR                 String jarName   getJarName            return jarName contains   jar               public static String getProgramDirectory                 if  runningFromJAR                          return getCurrentJARDirectory              else                       return getCurrentProjectDirectory                         private static String getCurrentProjectDirectory                 return new File     getAbsolutePath               private static String getCurrentJARDirectory                 try                       return new File ProgramDirectoryUtilities class getProtectionDomain   getCodeSource   getLocation   toURI   getPath    getParent              catch  URISyntaxException exception                        exception printStackTrace                       return null            Simply call getProgramDirectory   and you should be good either way

[java] How to get the real path of Java application at runtime?

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