[javascript] convert string into array of integers

I want to convert the following string '14 2' into an array of two integers. How can I do it ?

A quick one for modern browsers:

'14 2'.split(' ').map(Number);

// [14, 2]`

First split the string on spaces:

var result = '14 2'.split(' ');

Then convert the result array of strings into integers:

for (var i in result) {
    result[i] = parseInt(result[i], 10);
}

An alternative to Tushar Gupta answer would be :

'14 2'.split(' ').map(x=>+x);

// [14, 2]`

In code golf you save 1 character. Here the "+" is "unary plus" operator, works like parseInt.

The point against parseInt-approach:

There's no need to use lambdas and/or give radix parameter to parseInt, just use parseFloat or Number instead.

Reasons:

1. It's working:

   var src = "1,2,5,4,3";
   var ids = src.split(',').map(parseFloat); // [1, 2, 5, 4, 3]
   
   var obj = {1: ..., 3: ..., 4: ..., 7: ...};
   var keys= Object.keys(obj); // ["1", "3", "4", "7"]
   var ids = keys.map(parseFloat); // [1, 3, 4, 7]
   
   var arr = ["1", 5, "7", 11];
   var ints= arr.map(parseFloat); // [1, 5, 7, 11]
   ints[1] === "5" // false
   ints[1] === 5   // true
   ints[2] === "7" // false
   ints[2] === 7   // true
   

2. It's shorter.

3. It's a tiny bit quickier and takes advantage of cache, when parseInt-approach - doesn't:

     // execution time measure function
     // keep it simple, yeah?
   > var f = (function (arr, c, n, m) {
         var i,t,m,s=n();
         for(i=0;i++<c;)t=arr.map(m);
         return n()-s
     }).bind(null, "2,4,6,8,0,9,7,5,3,1".split(','), 1000000, Date.now);
   
   > f(Number) // first launch, just warming-up cache
   > 3971 // nice =)
   
   > f(Number)
   > 3964 // still the same
   
   > f(function(e){return+e})
   > 5132 // yup, just little bit slower
   
   > f(function(e){return+e})
   > 5112 // second run... and ok.
   
   > f(parseFloat)
   > 3727 // little bit quicker than .map(Number)
   
   > f(parseFloat)
   > 3737 // all ok
   
   > f(function(e){return parseInt(e,10)})
   > 21852 // awww, how adorable...
   
   > f(function(e){return parseInt(e)})
   > 22928 // maybe, without '10'?.. nope.
   
   > f(function(e){return parseInt(e)})
   > 22769 // second run... and nothing changes.
   
   > f(Number)
   > 3873 // and again
   > f(parseFloat)
   > 3583 // and again
   > f(function(e){return+e})
   > 4967 // and again
   
   > f(function(e){return parseInt(e,10)})
   > 21649 // dammit 'parseInt'! >_<
   

Notice: In Firefox parseInt works about 4 times faster, but still slower than others. In total: +e < Number < parseFloat < parseInt

If the numbers can be separated by more than one space, it is safest to split the string on one or more consecutive whitespace characters (which includes tabs and regular spaces). With a regular expression, this would be \s+.

You can then map each element using the Number function to convert it. Note that parseInt will not work (i.e. arr.map(parseInt)) because map passes three arguments to the mapping function: the element, the index, and the original array. parseInt accepts the base or radix as the second parameter, so it will end up taking the index as the base, often resulting in many NaNs in the result. However, Number ignores any arguments other than the first, so it works directly.

const str = '1\t\t2   3 4';
const result = str.split(/\s+/).map(Number); //[1,2,3,4]

You could also use an anonymous function for the mapping callback with the unary plus operator to convert each element to a number.

const str = '1\t\t2   3 4';
const result = str.split(/\s+/).map(x => +x); //[1,2,3,4]

With an anonymous function for the callback, you can decide what parameters to use, so parseInt can also work.

const str = '1\t\t2   3 4';
const result = str.split(/\s+/).map(x => parseInt(x)); //[1,2,3,4]

us the split function:

var splitresult = "14 2".split(" ");

Better one line solution:

var answerInt = [];
var answerString = "1 2 3 4";
answerString.split(' ').forEach(function (item) {
   answerInt.push(parseInt(item))
});

SO...older thread, I know, but...

EDIT

@RoccoMusolino had a nice catch; here's an alternative:

TL;DR:

 const intArray = [...("5 6 7 69 foo 0".split(' ').filter(i => /\d/g.test(i)))]

WRONG: "5 6 note this foo".split(" ").map(Number).filter(Boolean); // [5, 6]

There is a subtle flaw in the more elegant solutions listed here, specifically @amillara and @Marcus' otherwise beautiful answers.

The problem occurs when an element of the string array isn't integer-like, perhaps in a case without validation on an input. For a contrived example...

The problem:

var effedIntArray = "5 6 7 69 foo".split(' ').map(Number); // [5, 6, 7, 69, NaN]

Since you obviously want a PURE int array, that's a problem. Honestly, I didn't catch this until I copy-pasted SO code into my script... :/

The (slightly-less-baller) fix:

var intArray = "5 6 7 69 foo".split(" ").map(Number).filter(Boolean); // [5, 6, 7, 69]

So, now even when you have crap int string, your output is a pure integer array. The others are really sexy in most cases, but I did want to offer my mostly rambly w'actually. It is still a one-liner though, to my credit...

Hope it saves someone time!

var result = "14 2".split(" ").map(function(x){return parseInt(x)});

Just for fun I thought I'd throw a forEach(f()) solution in too.

var a=[];
"14 2".split(" ").forEach(function(e){a.push(parseInt(e,10))});

// a = [14,2]

let idsArray = ids.split(',').map((x) => parseInt(x));