How to open the command prompt and insert commands using Java

Question

Is it possible to open the command prompt  and I guess any other terminal for other systems   and execute commands in the newly opened window    Currently what I have is this   Runtime rt   Runtime getRuntime    rt exec new String    cmd exe    c   start       I ve tried adding the next command after the  start   I ve tried running another rt exec containing my command  but I can t find a way to make it work    If it matters  I m trying to run a command similar to this   java -flag -flag -cp terminal-based-program jar   EDIT Unfortunately I have had some strange findings  I ve been able to successfully launch the command prompt and pass a command using this   rt exec  cmd exe  c start command      However  it only seems to work with one command  Because  if I try to use the command separator like this   cmd exe  c start command amp command2   the second command is passed through the background  the way it would if I just used rt exec  command2       Now the problem here is  I realized that I need to change the directory the command prompt is running in  because if I just use the full path to the jar file  the jar file incorrectly reads the data from the command prompt s active directory  not the jar s directory which contains its resources

User · Answer

You just need to append your command after start in the string that you are passing   String command    cmd exe  c start     your command     Process child   Runtime getRuntime   exec command

User · Answer

You have to set all     quotes  carefully  The parameter  k is used to leave the command prompt open after the execution    1  to combine 2 commands use  for example pause and ipconfig   Runtime getRuntime      exec  cmd  c start cmd exe  k   pause  amp  amp  ipconfig     null  selectedFile getParentFile       2  to show the content of a file use  MORE is a command line viewer on Windows   File selectedFile   new File pathToFile   Runtime getRuntime      exec  cmd  c start cmd exe  k   MORE       selectedFile getName             null  selectedFile getParentFile       One nesting quote    is for the command and the file name  the second quote    is for the filename itself  for spaces etc  in the name particularly

User · Answer

public static void main String   args        try           String ss   null          Process p   Runtime getRuntime   exec  cmd exe  c start dir             BufferedWriter writeer   new BufferedWriter new OutputStreamWriter p getOutputStream              writeer write  dir            writeer flush            BufferedReader stdInput   new BufferedReader new InputStreamReader p getInputStream              BufferedReader stdError   new BufferedReader new InputStreamReader p getErrorStream              System out println  Here is the standard output of the command  n            while   ss   stdInput readLine       null                System out println ss                     System out println  Here is the standard error of the command  if any   n            while   ss   stdError readLine       null                System out println ss                    catch  IOException e            System out println  FROM CATCH    e toString

User · Answer

Please  place your command in a parameter like the mentioned below   Runtime getRuntime   exec  cmd exe  c start cmd  k    parameter

User · Answer

String   command     cmd exe      c    start     cmd exe      k        dir  amp  amp  ipconfig         ProcessBuilder probuilder   new ProcessBuilder  command    probuilder directory new File  D   Folder1     Process process   probuilder start

User · Answer

The following works for me on Snow Leopard   Runtime rt   Runtime getRuntime    String   testArgs     touch    TEST    rt exec testArgs     Thing is  if you want to read the output of that command  you need to read the input stream of the process  For instance   Process pr   rt exec arguments   BufferedReader r   new BufferedReader new InputStreamReader pr getInputStream        Allows you to read the line-by-line output of the command pretty easily   The problem might also be that MS-DOS does not interpret your order of arguments to mean  start a new command prompt   Your array should probably be     start    cmd exe     c    To open commands in the new command prompt  you d have to use the Process reference  But I m not sure why you d want to do that when you can just use exec  as the person before me commented

User · Answer

I know that people recommend staying away from rt exec String   but this works  and I don t know how to change it into the array version   rt exec  cmd exe  c cd     new dir      amp  start cmd exe  k   java -flag -flag -cp terminal-based-program jar

User · Answer

If you are running two commands at once just to change the directory the command prompt runs in  there is an overload for the Runtime exec method that lets you specify the current working directory  Like   Runtime rt   Runtime getRuntime    rt exec  cmd exe  c start command   null  new File newDir      This will open command prompt in the directory at newDir  I think your solution works as well  but this keeps your command string or array a little cleaner   There is an overload for having the command as a string and having the command as a String array   You may find it even easier  though  to use the ProcessBuilder  which has a directory method to set your current working directory   Hope this helps

User · Answer

You can use any on process for dynamic path on command prompt  Process p   Runtime getRuntime   exec  cmd exe  c start dir     Process p   Runtime getRuntime   exec  cmd exe  c start cd   E   rakhee  Obligation Extractions    amp  amp  dir    Process p   Runtime getRuntime   exec  cmd exe  c start cd   E   oxyzen-workspace  BrightleafDesktop  Obligation Extractions    amp  amp  dir

[java] How to open the command prompt and insert commands using Java?

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