Is it possible to check if an element's CSS display == block
or none
using JavaScript?
This question is related to
javascript
css
If the style was declared inline or with JavaScript, you can just get at the style
object:
return element.style.display === 'block';
Otherwise, you'll have to get the computed style, and there are browser inconsistencies. IE uses a simple currentStyle
object, but everyone else uses a method:
return element.currentStyle ? element.currentStyle.display :
getComputedStyle(element, null).display;
The null
was required in Firefox version 3 and below.
With pure javascript you can check the style.display
property. With jQuery you can use $('#id').css('display')
yes.
var displayValue = document.getElementById('yourid').style.display;
You can check it with for example jQuery:
$("#elementID").css('display');
It will return string with information about display property of this element.
This answer is not exactly what you want, but it might be useful in some cases. If you know the element has some dimensions when displayed, you can also use this:
var hasDisplayNone = (element.offsetHeight === 0 && element.offsetWidth === 0);
EDIT: Why this might be better than direct check of CSS display
property? Because you do not need to check all parent elements. If some parent element has display: none
, its children are hidden too but still has element.style.display !== 'none'
.
For jQuery, do you mean like this?
$('#object').css('display');
You can check it like this:
if($('#object').css('display') === 'block')
{
//do something
}
else
{
//something else
}
To find out if it's visible with plain JavaScript, check whether the display property is 'none' (don't check for 'block', it could also be blank or 'inline' and still be visible):
var isVisible = (elt.style.display != "none");
If you are using jQuery, you can use this instead:
var isVisible = $elt.is(":visible");
Basic JavaScript:
if (document.getElementById("elementId").style.display == 'block') {
alert('this Element is block');
}
Source: Stackoverflow.com