Replace last occurrence of character in string

Question

Is there an easy way in javascript to replace the last occurrence of an      underscore  in a given string

User · Answer

Another super clear way of doing this could be as follows    let modifiedString   originalString     split     reverse   join         replace              split     reverse   join

User · Answer

x000D   x000D  var someString      n        n   ---  n         x000D  var toRemove      n         should find  amp  remove last occurrence  x000D   x000D  function removeLast s  r   x000D    s   s split r  x000D    return s slice 0 -1  join r    s pop   x000D    x000D   x000D  console log  x000D    removeLast someString  toRemove  x000D    x000D   x000D   x000D    Breakdown   s   s split toRemove                          ---            s slice 0 -1                                   ---        s slice 0 -1  join toRemove                  ---    s pop

User · Answer

Keep it simple  var someString    a b c   var newCharacter         var newString   someString substring 0  someString lastIndexOf         newCharacter   someString substring someString lastIndexOf      1

User · Answer

No need for jQuery nor regex assuming the character you want to replace exists  in the string   Replace last char in a string  str   str substring 0 str length-2  otherchar  Replace last underscore in a string  var pos   str lastIndexOf       str   str substring 0 pos    otherchar   str substring pos 1    or use one of the regular expressions from the other answers   x000D   x000D  var str1    Replace the full stop with a questionmark   x000D  var str2    Replace last   with another char other than the underscore   near the end  x000D   x000D     Replace last char in a string x000D   x000D  console log  x000D    str1 substring 0 str1 length-2      x000D      x000D     alternative syntax x000D  console log  x000D    str1 slice 0 -1      x000D    x000D   x000D     Replace last underscore in a string  x000D   x000D  var pos   str2 lastIndexOf       otherchar        x000D  console log  x000D    str2 substring 0 pos    otherchar   str2 substring pos 1  x000D    x000D     alternative syntax x000D   x000D  console log  x000D    str2 slice 0 pos    otherchar   str2 slice pos 1  x000D    x000D   x000D   x000D

User · Answer

What about this   function replaceLast x  y  z     var a   x split        a x lastIndexOf y     z    return a join         replaceLast  Hello world     l    x       Hello worxd

User · Answer

x000D   x000D         Define variables x000D      let haystack    I do not want to replace this  but this  x000D      let needle    this  x000D      let replacement    hey it works     x000D       x000D         Reverse it x000D      haystack   Array from haystack  reverse   join     x000D      needle   Array from needle  reverse   join     x000D      replacement   Array from replacement  reverse   join     x000D       x000D         Make the replacement x000D      haystack   haystack replace needle  replacement  x000D       x000D         Reverse it back x000D      let results   Array from haystack  reverse   join     x000D      console log results  x000D          I do not want to replace this  but hey it works     x000D   x000D   x000D

User · Answer

You can use this code   x000D   x000D  var str  test String ABC   x000D  var strReplacedWith   and    x000D  var currentIndex   str lastIndexOf       x000D  str   str substring 0  currentIndex    strReplacedWith   str substring currentIndex   1  str length   x000D   x000D  alert str   x000D   x000D   x000D

User · Answer

This is very similar to mplungjan s answer  but can be a bit easier  especially if you need to do other string manipulation right after and want to keep it as an array  Anyway  I just thought I d put it out there in case someone prefers it     x000D   x000D  var str    a b c   x000D  str   str split          a       b       c   x000D  str splice str lastIndexOf      1  -        a       b   -   c   x000D  str   str join         a b-c  x000D   x000D   x000D    The     can be swapped out with the char you want to replace   And the  -  can be replaced with the char or string you want to replace it with

User · Answer

This is a recursive way that removes multiple occurrences of  endchar     x000D   x000D  function TrimEnd str  endchar    x000D    while  str endsWith endchar   amp  amp  str         amp  amp  endchar           x000D      str   str slice 0  -1   x000D      x000D    return str  x000D    x000D   x000D  var res   TrimEnd  Look at me  I m a string without dots at the end            x000D  console log res  x000D   x000D   x000D

User · Answer

You don t need jQuery  just a regular expression   This will remove the last underscore    x000D   x000D  var str    a b c   x000D  console log   str replace                1        a bc x000D   x000D   x000D    This will replace it with the contents of the variable replacement    x000D   x000D  var str    a b c   x000D      replacement        x000D   x000D  console log   str replace              replacement     1        a b c x000D   x000D   x000D

User · Answer

Reverse the string  replace the char  reverse the string    Here is a post for reversing a string in javascript   How do you reverse a string in place in JavaScript

[javascript] Replace last occurrence of character in string

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