Get child Node of another Node given node name

Question

I have an XML like this    lt documentslist gt     lt document gt       lt docnumber gt 1 lt  docnumber gt       lt docname gt Declaration of Human Rights lt  docname gt       lt aoo gt lib lt  aoo gt     lt  document gt     lt document gt       lt docnumber gt 2 lt  docnumber gt       lt docname gt Fair trade lt  docname gt       lt aoo gt lib lt  aoo gt     lt  document gt     lt document gt       lt docnumber gt 3 lt  docnumber gt       lt docname gt The wars for water lt  docname gt       lt aoo gt lib lt  aoo gt     lt  document gt     lt  -- etc  -- gt   lt  documentslist gt    I have this code     XML parsing Document docsDoc   null  try       DocumentBuilder db   dbf newDocumentBuilder        docsDoc   db parse new InputSource new StringReader xmlWithDocs       catch ParserConfigurationException e   e printStackTrace     catch SAXException e   e printStackTrace     catch IOException e   e printStackTrace       retrieve document elements NodeList docs   docsDoc getElementsByTagName  document     if  docs getLength    gt  0         print a row for each document     for  int i 0  i lt docs getLength    i               get current document         Node doc   docs item i             print a cell for some document children         for  int j 0  j lt columns length  j                 Node cell                print docname             cell   doc getElementsByTagName  docname   item 0     doesn t work             System out print cell getTextContent       t                  print aoo             cell   doc getElementsByTagName  aoo   item 0     doesn t work             System out print cell getTextContent       t                      System out println              But  as you know Node hasn t got getElementsByTagName method    Only Document has it  But I can t do docsDoc getElementsByTagName  aoo    because it will return me all  lt aoo gt  nodes  not only the one existing in the  lt document gt  node I m inspecting   How could I do it  Thanks

User · Answer

You should read it recursively  some time ago I had the same question and solve with this code   public void proccessMenuNodeList NodeList nl  JMenuBar menubar        for  int i   0  i  lt  nl getLength    i              proccessMenuNode nl item i   menubar            public void proccessMenuNode Node n  Container parent        if  n getNodeName   equals  menu            return      Element element    Element  n      String type   element getAttribute  type        String name   element getAttribute  name        if  type equals  menu              NodeList nl   element getChildNodes            JMenu menu   new JMenu name            for  int i   0  i  lt  nl getLength    i                proccessMenuNode nl item i   menu            parent add menu         else if  type equals  item              JMenuItem item   new JMenuItem name           parent add item             Probably you can adapt it for your case

User · Answer

xn list of parent nodes                       foreach  XmlNode xn in xnList                                                   foreach  XmlNode child in xn ChildNodes                 if  child Name Equals  name                           name   child InnerText                     if  child Name Equals  age                          age   child InnerText

User · Answer

If the Node is not just any node  but actually an Element  it could also be e g  an attribute or a text node   you can cast it to Element and use getElementsByTagName

User · Answer

Check if the Node is a Dom Element  cast  and call getElementsByTagName    Node doc   docs item i   if doc instanceof Element        Element docElement    Element doc              cell   doc getElementsByTagName  aoo   item 0

[java] Get child Node of another Node, given node name

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