How to extract the file name from URI returned from Intent ACTION GET CONTENT

Question

I am using 3rd party file manager to pick a file  PDF in my case  from the file system    This is how I launch the activity   Intent intent   new Intent Intent ACTION GET CONTENT   intent setType getString R string app pdf mime type    intent addCategory Intent CATEGORY OPENABLE    String chooserName   getString R string Browse   Intent chooser   Intent createChooser intent  chooserName    startActivityForResult chooser  ActivityRequests BROWSE     This is what I have in onActivityResult   Uri uri   data getData    if  uri    null        if  uri toString   startsWith  file               fileName   uri getPath          else      uri startsWith  content             Cursor c   getContentResolver   query uri  null  null  null  null            if  c    null  amp  amp  c moveToFirst                   int id   c getColumnIndex Images Media DATA               if  id    -1                    fileName   c getString id                                     Code snippet is borrowed from Open Intents File Manager instructions available here  http   www openintents org en node 829  The purpose of if-else is backwards compatibility  I wonder if this is a best way to get the file name as I have found that other file managers return all kind of things    For example  Documents ToGo return something like the following    content   com dataviz dxtg documentprovider document file 3A 2F 2F 2Fsdcard 2Fdropbox 2FTransfer 2Fconsent pdf   on which getContentResolver   query   returns null   To make things more interesting  unnamed file manager  I got this URI from client log  returned something like      sdcard downloads  bin    Is there a preferred way of extracting the file name from URI or one should resort to string parsing

User · Answer

Combination of all the answers

Here is what I have arrived at after a read of all the answers presented here as well what some Airgram has done in their SDKs - A utility that I have open sourced on Github:

https://github.com/mankum93/UriUtilsAndroid/tree/master/app/src/main/java/com/androiduriutils

Usage

As simple as calling, UriUtils.getDisplayNameSize(). It provides both the name and size of the content.

Note: Only works with a content:// Uri

Here is a glimpse on the code:

/**
 * References:
 * - https://www.programcreek.com/java-api-examples/?code=MLNO/airgram/airgram-master/TMessagesProj/src/main/java/ir/hamzad/telegram/MediaController.java
 * - https://stackoverflow.com/questions/5568874/how-to-extract-the-file-name-from-uri-returned-from-intent-action-get-content
 *
 * @author [email protected]/2HjxA0C
 * Created on: 03-07-2020
 */
public final class UriUtils {


    public static final int CONTENT_SIZE_INVALID = -1;

    /**
     * @param context context
     * @param contentUri content Uri, i.e, of the scheme <code>content://</code>
     * @return The Display name and size for content. In case of non-determination, display name
     * would be null and content size would be {@link #CONTENT_SIZE_INVALID}
     */
    @NonNull
    public static DisplayNameAndSize getDisplayNameSize(@NonNull Context context, @NonNull Uri contentUri){

        final String scheme = contentUri.getScheme();
        if(scheme == null || !scheme.equals(ContentResolver.SCHEME_CONTENT)){
            throw new RuntimeException("Only scheme content:// is accepted");
        }

        final DisplayNameAndSize displayNameAndSize = new DisplayNameAndSize();
        displayNameAndSize.size = CONTENT_SIZE_INVALID;

        String[] projection = new String[]{MediaStore.Images.Media.DATA, OpenableColumns.DISPLAY_NAME, OpenableColumns.SIZE};
        Cursor cursor = context.getContentResolver().query(contentUri, projection, null, null, null);
        try {
            if (cursor != null && cursor.moveToFirst()) {

                // Try extracting content size

                int sizeIndex = cursor.getColumnIndex(OpenableColumns.SIZE);
                if (sizeIndex != -1) {
                    displayNameAndSize.size = cursor.getLong(sizeIndex);
                }

                // Try extracting display name
                String name = null;

                // Strategy: The column name is NOT guaranteed to be indexed by DISPLAY_NAME
                // so, we try two methods
                int nameIndex = cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);
                if (nameIndex != -1) {
                    name = cursor.getString(nameIndex);
                }

                if (nameIndex == -1 || name == null) {
                    nameIndex = cursor.getColumnIndex(MediaStore.Images.Media.DATA);
                    if (nameIndex != -1) {
                        name = cursor.getString(nameIndex);
                    }
                }
                displayNameAndSize.displayName = name;
            }
        }
        finally {
            if(cursor != null){
                cursor.close();
            }
        }

        // We tried querying the ContentResolver...didn't work out
        // Try extracting the last path segment
        if(displayNameAndSize.displayName == null){
            displayNameAndSize.displayName = contentUri.getLastPathSegment();
        }

        return displayNameAndSize;
    }
}

User · Answer

For Kotlin  You can use something like this    object FileUtils       fun Context getFileName uri  Uri   String            when  uri scheme                ContentResolver SCHEME FILE - gt  File uri path  name             ContentResolver SCHEME CONTENT - gt  getCursorContent uri              else - gt  null                private fun Context getCursorContent uri  Uri   String             try               contentResolver query uri  null  null  null  null   let   cursor - gt                  cursor run                       if  moveToFirst    getString getColumnIndex OpenableColumns DISPLAY NAME                       else null                   also   cursor close                             catch  e   Exception    null

User · Answer

I got some information from the developer s website      val cursor   context contentResolver query fileUri  null  null  null  null                  val nameIndex   cursor getColumnIndex OpenableColumns DISPLAY NAME  val sizeIndex   cursor getColumnIndex OpenableColumns SIZE  cursor moveToFirst   val fileName   cursor getString nameIndex  val size   cursor getLong sizeIndex           Don t forget to close resources Retrieving file information

User · Answer

The most condensed version   public String getNameFromURI Uri uri        Cursor c   getContentResolver   query uri  null  null  null  null       c moveToFirst        return c getString c getColumnIndex OpenableColumns DISPLAY NAME

User · Answer

public String getFilename          Intent intent   getIntent        String name   intent getData   getLastPathSegment        return name        Uri uri getIntent   getData        String fileName   null      Context context getApplicationContext        String scheme   uri getScheme        if  scheme equals  file              fileName   uri getLastPathSegment              else if  scheme equals  content              String   proj     MediaStore Video Media TITLE            Uri contentUri   null          Cursor cursor   context getContentResolver   query uri  proj  null  null  null           if  cursor    null  amp  amp  cursor getCount      0                int columnIndex   cursor getColumnIndexOrThrow MediaStore Video Media TITLE               cursor moveToFirst                fileName   cursor getString columnIndex                       return fileName

User · Answer

Easiest ways to get file name   val fileName   File uri path  name    or val fileName   uri pathSegments last     If they don t give you the right name you should use   fun Uri getName context  Context   String       val returnCursor   context contentResolver query this  null  null  null  null      val nameIndex   returnCursor getColumnIndex OpenableColumns DISPLAY NAME      returnCursor moveToFirst       val fileName   returnCursor getString nameIndex      returnCursor close       return fileName

User · Answer

My version of the answer is actually very similar to the  Stefan Haustein  I found the answer on Android Developer page Retrieving File Information  the information here is even more condensed on this specific topic than on Storage Access Framework guide site  In the result from the query the column index containing file name is OpenableColumns DISPLAY NAME  None of other answers solutions for column indexes worked for me  Below is the sample function            param uri uri of file      param contentResolver access to server app      return the name of the file      def extractFileName uri  Uri  contentResolver  ContentResolver   Option String           var fileName  Option String    None     if  uri getScheme equals  file               fileName   Option uri getLastPathSegment        else if  uri getScheme equals  content               var cursor  Cursor   null         try                   Query the server app to get the file s display name and size              cursor   contentResolver query uri  null  null  null  null                  Get the column indexes of the data in the Cursor                 move to the first row in the Cursor  get the data              if  cursor    null  amp  amp  cursor moveToFirst                       val nameIndex   cursor getColumnIndex OpenableColumns DISPLAY NAME                  fileName   Option cursor getString nameIndex                            finally                if  cursor    null                    cursor close                                        fileName

User · Answer

Stefan Haustein function for xamarin c     public string GetFilenameFromURI Android Net Uri uri                        string result   null              if  uri Scheme     content                                 using  var cursor   Application Context ContentResolver Query uri  null  null  null  null                                         try                                               if  cursor    null  amp  amp  cursor MoveToFirst                                                          result   cursor GetString cursor GetColumnIndex OpenableColumns DisplayName                                                                        finally                                               cursor Close                                                                      if  result    null                                result   uri Path                  int cut   result LastIndexOf                       if  cut    -1                                        result   result Substring cut   1                                               return result

User · Answer

First  you need to convert your URI object to URL object  and then use File object to retrieve a file name   try               URL videoUrl   uri toURL            File tempFile   new File videoUrl getFile             String fileName   tempFile getName              catch  Exception e                 That s it  very easy

User · Answer

I m using something like this   String scheme   uri getScheme    if  scheme equals  file          fileName   uri getLastPathSegment      else if  scheme equals  content          String   proj     MediaStore Images Media TITLE        Cursor cursor   context getContentResolver   query contentUri  proj  null  null  null       if  cursor    null  amp  amp  cursor getCount      0            int columnIndex   cursor getColumnIndexOrThrow MediaStore Images Media TITLE           cursor moveToFirst            fileName   cursor getString columnIndex             if  cursor    null            cursor close

User · Answer

Please try this      private String displayName Uri uri                  Cursor mCursor                        getApplicationContext   getContentResolver   query uri  null  null  null  null                int indexedname   mCursor getColumnIndex OpenableColumns DISPLAY NAME                mCursor moveToFirst                 String filename   mCursor getString indexedname                mCursor close                 return filename

User · Answer

If you want it short this should work   Uri uri  data getData    File file  new File uri getPath     file getName

User · Answer

String Fpath   getPath this  uri    File file   new File Fpath   String filename   file getName

User · Answer

This actually worked for me   private String uri2filename          String ret      String scheme   uri getScheme         if  scheme equals  file              ret   uri getLastPathSegment              else if  scheme equals  content              Cursor cursor   getContentResolver   query uri  null  null  null  null           if  cursor    null  amp  amp  cursor moveToFirst                  ret   cursor getString cursor getColumnIndex OpenableColumns DISPLAY NAME                      return ret

User · Answer

Taken from Retrieving File information   Android developers  Retrieving a File s name   private String queryName ContentResolver resolver  Uri uri        Cursor returnCursor               resolver query uri  null  null  null  null       assert returnCursor    null      int nameIndex   returnCursor getColumnIndex OpenableColumns DISPLAY NAME       returnCursor moveToFirst        String name   returnCursor getString nameIndex       returnCursor close        return name

User · Answer

I use below code to get File Name  amp  File Size from Uri in my project          Used to get file detail from uri      lt p gt     1  Used to get file detail  name  amp  size  from uri     2  Getting file details from uri is different for different uri scheme     2 a  For  File Uri Scheme  - We will get file from uri  amp  then get its details     2 b  For  Content Uri Scheme  - We will get the file details by querying content resolver         param uri Uri      return file detail      public static FileDetail getFileDetailFromUri final Context context  final Uri uri        FileDetail fileDetail   null      if  uri    null            fileDetail   new FileDetail               File Scheme          if  ContentResolver SCHEME FILE equals uri getScheme                   File file   new File uri getPath                 fileDetail fileName   file getName                fileDetail fileSize   file length                         Content Scheme          else if  ContentResolver SCHEME CONTENT equals uri getScheme                   Cursor returnCursor                       context getContentResolver   query uri  null  null  null  null               if  returnCursor    null  amp  amp  returnCursor moveToFirst                      int nameIndex   returnCursor getColumnIndex OpenableColumns DISPLAY NAME                   int sizeIndex   returnCursor getColumnIndex OpenableColumns SIZE                   fileDetail fileName   returnCursor getString nameIndex                   fileDetail fileSize   returnCursor getLong sizeIndex                   returnCursor close                                      return fileDetail            File Detail      lt p gt     1  Model used to hold file details      public static class FileDetail           fileSize      public String fileName          fileSize in bytes      public long fileSize                  Constructor              public FileDetail

User · Answer

If you want to have the filename with extension I use this function to get it   It also works with google drive file picks  public static String getFileName Uri uri        String result         if uri is content     if  uri getScheme      null  amp  amp  uri getScheme   equals  content              Cursor cursor   global getInstance   context getContentResolver   query uri  null  null  null  null           try               if  cursor    null  amp  amp  cursor moveToFirst                        local filesystem                 int index   cursor getColumnIndex   data                    if index    -1                        google drive                     index   cursor getColumnIndex   display name                    result   cursor getString index                   if result    null                      uri   Uri parse result                   else                     return null                          finally               cursor close                         result   uri getPath           get filename   ext of path     int cut   result lastIndexOf           if  cut    -1          result   result substring cut   1       return result

User · Answer

developer android com has nice example code for this  https   developer android com guide topics providers document-provider html  A condensed version to just extract the file name  assuming  this  is an Activity    public String getFileName Uri uri      String result   null    if  uri getScheme   equals  content          Cursor cursor   getContentResolver   query uri  null  null  null  null       try         if  cursor    null  amp  amp  cursor moveToFirst              result   cursor getString cursor getColumnIndex OpenableColumns DISPLAY NAME                  finally         cursor close                if  result    null        result   uri getPath        int cut   result lastIndexOf           if  cut    -1          result   result substring cut   1               return result

[android] How to extract the file name from URI returned from Intent.ACTION_GET_CONTENT?

Combination of all the answers

Usage

Examples related to android