How to check if an integer is in a given range

Question

Hoping for something more elegant than  if  i gt 0  amp  amp  i lt 100

User · Answer

I think its already elegant way for comparing range. But, this approach cause you to write extra unit tests to satisfy all && cases.

So, you can use any of the below approach to avoid writing extra unit tests.

Using Java 8 Streams:

if(IntStream.rangeClosed(0,100).boxed().collect(Collectors.toList()).contains(i))

Using Math class:

if(Math.max(0, i) == Math.min(i, 100))

Personally I recommend the second approach because it won't end up creating an Array of the size equal to the range you want to check.

User · Answer

Try    if  i gt 0  amp  amp  i lt 100        it will work at least

User · Answer

If you re looking for something more original than   if  i  gt  0  amp  amp  i  lt  100    you can try this  import static java lang Integer compare      if compare i  0   gt  compare i  100

User · Answer

Range lt Long gt  timeRange   Range create model getFrom    model getTo         if timeRange contains systemtime            Toast makeText context   green     Toast LENGTH SHORT  show

User · Answer

Use this code    if  lowerBound  lt   val  amp  amp  val  lt  upperBound  or if  lowerBound  lt   val  amp  amp  val  lt   upperBound

User · Answer

if i  lt   0    i   100   It will work

User · Answer

if you are using Spring data you can also use the Range object from Spring    range   new org springframework data domain Range 3  8   range contains 5  will return true

User · Answer

For those using commons lang an option is to use Range   Range lt Integer gt  myRange   Range between 100  500   if  myRange contains 200           do something     Also see  how to construct a apache commons 3 1 Range lt Integer gt  object

User · Answer

val   val  lt  MIN   MIN     val  gt  MAX   MAX   val

User · Answer

You could add spacing     if  i  gt  0  amp  amp  i  lt  100

User · Answer

If you are confident that numbers are stored in 2 s complement form    return    x-low   lt    high-low      A more general and safer solution would be    return   x-high   x-low   lt   0

User · Answer

I think   if  0  lt  i  amp  amp  i  lt  100     is more elegant  Looks like maths equation    If you are looking for something special you can try   Math max 0  i     Math min i  100    at least it uses library

User · Answer

Google s Java Library Guava also implements Range  import com google common collect Range   Range lt Integer gt  open   Range open 1  5   System out println open contains 1       false System out println open contains 3       true System out println open contains 5       false  Range lt Integer gt  closed   Range closed 1  5   System out println closed contains 1       true System out println closed contains 3       true System out println closed contains 5       true  Range lt Integer gt  openClosed   Range openClosed 1  5   System out println openClosed contains 1       false System out println openClosed contains 3       true System out println openClosed contains 5       true

User · Answer

This guy made a nice Range class   Its use however will not yield nice code as it s a generic class  You d have to type something like   if  new Range lt Integer gt  0  100  contains i     or  somewhat better if you implement first    class IntRange extends Range lt Integer gt       if  new IntRange 0 100  contains i     Semantically both are IMHO nicer than what Java offers by default  but the memory overhead  performance degradation and more typing overall are hadly worth it  Personally  I like mdma s approach better

User · Answer

ValueRange range   java time temporal ValueRange of minValue  maxValue   range isValidIntValue x     it returns true if  minValue  lt   x  lt   MaxValue - i e within the range  it returns false if  x  lt  minValue or x   maxValue  - i e outofrange  Use with if condition as shown below   int value   10  if ValueRange of 0  100  isValidIntValue value         System out println  Value is with in the Range       else       System out println  Value is out of the Range         below program checks  if any of the passed integer value in the hasTeen method is within the range of 13 inclusive  to 19 Inclusive      import java time temporal ValueRange      public class TeenNumberChecker        public static void main String   args            System out println hasTeen 9  99  19            System out println hasTeen 23  15  42            System out println hasTeen 22  23  34                public static boolean hasTeen int firstNumber  int secondNumber  int thirdNumber             ValueRange range   ValueRange of 13  19           System out println           Int validation Start                        System out println range isIntValue             System out println range isValidIntValue firstNumber            System out println range isValidIntValue secondNumber            System out println range isValidIntValue thirdNumber            System out println range isValidValue thirdNumber            System out println            Int validation End                           if  range isValidIntValue firstNumber     range isValidIntValue secondNumber     range isValidIntValue thirdNumber                 return true            else             return false                  OUTPUT        true as 19 is part of range   true as 15 is part of range   false as all three value passed out of range

User · Answer

I don t see how that s not elegant  but if you repeat the expression often  then it s a good idea to put it into a method  e g   class MathUtil      public static boolean betweenExclusive int x  int min  int max              return x gt min  amp  amp  x lt max               This is particularly true if you mix exclusive and inclusive comparisons  The method name can help avoid typos  such as using  lt  when  lt   should have been used  The method can also take care of ensuring that min  lt  max etc

User · Answer

if   0  lt  i  amp  amp  i  lt  100     if    a   lt   c  amp  amp  c  lt    z

User · Answer

That s how you check is an integer is in a range   Greater than the lower bound  less than the upper bound   Trying to be clever with subtraction will likely not do what you want

[java] How to check if an integer is in a given range?

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