std cin input with spaces

Question

include  lt string gt   std  string input  std  cin  gt  gt  input    The user wants to enter  Hello World   But cin fails at the space between the two words  How can I make cin take in the whole of Hello World   I m actually doing this with structs and cin getline doesn t seem to work  Here s my code   struct cd       std  string CDTitle 50       std  string Artist 50       int number of songs 50       std  cin getline library number of songs libNumber   250     This yields an error  Any ideas

User · Answer

THE C WAY  You can use gets function found in cstdio stdio h in c     include lt cstdio gt  int main     char name 256   gets name      for input puts name     for printing      THE C   WAY  gets is removed in c  11    Recommended  You can use getline cin name  which is in string h or cin getline name 256  which is in iostream itself    include lt iostream gt   include lt string gt  using namespace std  int main     char name1 256   string name2  cin getline name1 256      for input getline cin name2      for input cout lt  lt name1 lt  lt   n  lt  lt name2    for printing

User · Answer

You want to use the  getline function in cin    include  lt iostream gt  using namespace std   int main        char name 256   title 256      cout  lt  lt   Enter your name       cin getline  name 256      cout  lt  lt   Enter your favourite movie       cin getline  title 256      cout  lt  lt  name  lt  lt    s favourite movie is    lt  lt  title     return 0      Took the example from here  Check it out for more info and examples

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I rather use the following method to get the input    include  lt iostream gt   include  lt string gt   using namespace std   int main void        string name       cout  lt  lt   Hello  Input your name please         getline cin  name        return 0      It s actually super easy to use rather than defining the total length of array for a string which contains a space character

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It doesn t  fail   it just stops reading  It sees a lexical token as a  string    Use std  getline   int main        std  string name  title      std  cout  lt  lt   Enter your name        std  getline std  cin  name       std  cout  lt  lt   Enter your favourite movie        std  getline std  cin  title       std  cout  lt  lt  name  lt  lt    s favourite movie is    lt  lt  title      Note that this is not the same as std  istream  getline  which works with C-style char buffers rather than std  strings   Update  Your edited question bears little resemblance to the original   You were trying to getline into an int  not a string or character buffer  The formatting operations of streams only work with operator lt  lt  and operator gt  gt   Either use one of them  and tweak accordingly for multi-word input   or use getline and lexically convert to int after-the-fact

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The Standard Library provides an input function called ws  which consumes whitespace from an input stream   You can use it like this   std  string s  std  getline std  cin  gt  gt  std  ws  s

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You have to use cin getline     char input 100   cin getline input sizeof input

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Use     getline cin  input     the function can be found in    include  lt string gt

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How do I read a string from input  You can read a single  whitespace terminated word with std  cin like this   include lt iostream gt   include lt string gt  using namespace std   int main         cout  lt  lt   quot Please enter a word  n quot        string s      cin gt  gt s       cout  lt  lt   quot You entered  quot   lt  lt  s  lt  lt    n      Note that there is no explicit memory management and no fixed-sized buffer that you could possibly overflow  If you really need a whole line  and not just a single word  you can do this   include lt iostream gt   include lt string gt  using namespace std   int main         cout  lt  lt   quot Please enter a line  n quot        string s      getline cin s        cout  lt  lt   quot You entered  quot   lt  lt  s  lt  lt    n

[c++] std::cin input with spaces?

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