java lang IllegalArgumentException contains a path separator

Question

I have a filename in my code as    String NAME OF FILE    sdcard  imageq png   FileInputStream fis  this openFileInput NAME OF FILE      2nd line   I get an error on 2nd line       05-11 16 49 06 355  ERROR AndroidRuntime 4570   Caused by  java lang IllegalArgumentException  File   sdcard  imageq png contains a path separator   I tried this format also   String NAME OF FILE   sdcard imageq png

User · Answer

The solution is   FileInputStream fis   new FileInputStream  new File NAME OF FILE        2nd line   The openFileInput method doesn t accept path separators   Don t forget to  fis close      at the end

User · Answer

openFileInput   doesn t accept paths  only a file name if you want to access a path  use File file   new File path  and corresponding FileInputStream

User · Answer

This method opens a file in the private data area of the application  You cannot open any files in subdirectories in this area or from entirely other areas using this method  So use the constructor of the FileInputStream directly to pass the path with a directory in it

User · Answer

String all               try               BufferedReader br   new BufferedReader new FileReader filePath                String strLine              while   strLine   br readLine       null                   all   all   strLine                          catch  IOException e                Log e  notes err   e getLocalizedMessage

User · Answer

You cannot use path with directory separators directly  but you will have to make a file object for every directory   NOTE  This code makes directories  yours may not need that     File file  context getFilesDir    file mkdir     String   array filePath split       for int t 0  t lt  array length -1  t          file new File file array t        file mkdir       File f new File file array array length-1     RandomAccessFileOutputStream rvalue   new RandomAccessFileOutputStream f append

User · Answer

File file   context getFilesDir     file mkdir    String   array   filePath split        for int t   0  t  lt  array length - 1  t          file   new File file  array t         file mkdir      File f   new File file array array length- 1     RandomAccessFileOutputStream rvalue        new RandomAccessFileOutputStream f  append

User · Answer

I got the above error message while trying to access a file from Internal Storage using openFileInput   Dir data txt   method with subdirectory Dir    You cannot access sub-directories using the above method   Try something like   FileInputStream fIS   new FileInputStream  new File   Dir data txt

User · Answer

I solved this type of error by making a directory in the onCreate event  then accessing the directory by creating a new file object in a method that needs to do something such as save or retrieve a file in that directory  hope this helps    public class MyClass         private String state   public File myFilename     Override  protected void onCreate Bundle savedInstanceState     create your directory the user will be able to find     super onCreate savedInstanceState       if  Environment MEDIA MOUNTED equals state             myFilename   new File Environment getExternalStorageDirectory   toString       My Directory            if   myFilename exists                  myFilename mkdirs                         public void myMethod     File fileTo   new File myFilename toString       myPic png          use fileTo object to save your file in your new directory that was created in the onCreate method

[android] java.lang.IllegalArgumentException: contains a path separator

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