Suppose I have any variable, which is defined as follows:
var a = function() {/* Statements */};
I want a function which checks if the type of the variable is function-like. i.e. :
function foo(v) {if (v is function type?) {/* do something */}};
foo(a);
How can I check if the variable a
is of type Function
in the way defined above?
This question is related to
javascript
I found that when testing native browser functions in IE8, using toString
, instanceof
, and typeof
did not work. Here is a method that works fine in IE8 (as far as I know):
function isFn(f){
return !!(f && f.call && f.apply);
}
//Returns true in IE7/8
isFn(document.getElementById);
Alternatively, you can check for native functions using:
"getElementById" in document
Though, I have read somewhere that this will not always work in IE7 and below.
If you use Lodash you can do it with _.isFunction.
_.isFunction(function(){});
// => true
_.isFunction(/abc/);
// => false
_.isFunction(true);
// => false
_.isFunction(null);
// => false
This method returns true
if value is a function, else false
.
var foo = function(){};_x000D_
if (typeof foo === "function") {_x000D_
alert("is function")_x000D_
}
_x000D_
if (typeof v === 'function') {
// do something
}
Try the instanceof
operator: it seems that all functions inherit from the Function
class:
// Test data
var f1 = function () { alert("test"); }
var o1 = { Name: "Object_1" };
F_est = function () { };
var o2 = new F_est();
// Results
alert(f1 instanceof Function); // true
alert(o1 instanceof Function); // false
alert(o2 instanceof Function); // false
you should use typeOf
operator in js.
var a=function(){
alert("fun a");
}
alert(typeof a);// alerts "function"
I think you can just define a flag on the Function prototype and check if the instance you want to test inherited that
define a flag:
Function.prototype.isFunction = true;
and then check if it exist
var foo = function(){};
foo.isFunction; // will return true
The downside is that another prototype can define the same flag and then it's worthless, but if you have full control over the included modules it is the easiest way
The below seems to work for me as well (tested from node.js
):
var isFunction = function(o) {
return Function.prototype.isPrototypeOf(o);
};
console.log(isFunction(function(){})); // true
console.log(isFunction({})); // false
For those who's interested in functional style, or looks for more expressive approach to utilize in meta programming (such as type checking), it could be interesting to see Ramda library to accomplish such task.
Next code contains only pure and pointfree functions:
const R = require('ramda');
const isPrototypeEquals = R.pipe(Object.getPrototypeOf, R.equals);
const equalsSyncFunction = isPrototypeEquals(() => {});
const isSyncFunction = R.pipe(Object.getPrototypeOf, equalsSyncFunction);
As of ES2017, async
functions are available, so we can check against them as well:
const equalsAsyncFunction = isPrototypeEquals(async () => {});
const isAsyncFunction = R.pipe(Object.getPrototypeOf, equalsAsyncFunction);
And then combine them together:
const isFunction = R.either(isSyncFunction, isAsyncFunction);
Of course, function should be protected against null
and undefined
values, so to make it "safe":
const safeIsFunction = R.unless(R.isNil, isFunction);
And, complete snippet to sum up:
const R = require('ramda');
const isPrototypeEquals = R.pipe(Object.getPrototypeOf, R.equals);
const equalsSyncFunction = isPrototypeEquals(() => {});
const equalsAsyncFunction = isPrototypeEquals(async () => {});
const isSyncFunction = R.pipe(Object.getPrototypeOf, equalsSyncFunction);
const isAsyncFunction = R.pipe(Object.getPrototypeOf, equalsAsyncFunction);
const isFunction = R.either(isSyncFunction, isAsyncFunction);
const safeIsFunction = R.unless(R.isNil, isFunction);
// ---
console.log(safeIsFunction( function () {} ));
console.log(safeIsFunction( () => {} ));
console.log(safeIsFunction( (async () => {}) ));
console.log(safeIsFunction( new class {} ));
console.log(safeIsFunction( {} ));
console.log(safeIsFunction( [] ));
console.log(safeIsFunction( 'a' ));
console.log(safeIsFunction( 1 ));
console.log(safeIsFunction( null ));
console.log(safeIsFunction( undefined ));
However, note the this solution could show less performance than other available options due to extensive usage of higher-order functions.
An other simply way:
var fn = function () {}
if (fn.constructor === Function) {
// true
} else {
// false
}
Underscore.js uses a more elaborate but highly performant test:
_.isFunction = function(obj) {
return !!(obj && obj.constructor && obj.call && obj.apply);
};
See: http://jsperf.com/alternative-isfunction-implementations
EDIT: updated tests suggest that typeof might be faster, see http://jsperf.com/alternative-isfunction-implementations/4
@grandecomplex: There's a fair amount of verbosity to your solution. It would be much clearer if written like this:
function isFunction(x) {
return Object.prototype.toString.call(x) == '[object Function]';
}
Since node v0.11 you can use the standard util function :
var util = require('util');
util.isFunction('foo');
Something with more browser support and also include async functions could be:
const isFunction = value => value && (Object.prototype.toString.call(value) === "[object Function]" || "function" === typeof value || value instanceof Function);
and then test it like:
isFunction(isFunction); //true
isFunction(function(){}); //true
isFunction(()=> {}); //true
isFunction(()=> {return 1}); //true
isFunction(async function asyncFunction(){}); //true
isFunction(Array); //true
isFunction(Date); //true
isFunction(Object); //true
isFunction(Number); //true
isFunction(String); //true
isFunction(Symbol); //true
isFunction({}); //false
isFunction([]); //false
isFunction("function"); //false
isFunction(true); //false
isFunction(1); //false
isFunction("Alireza Dezfoolian"); //false
The solution as some previous answers has shown is to use typeof. the following is a code snippet In NodeJs,
function startx() {
console.log("startx function called.");
}
var fct= {};
fct["/startx"] = startx;
if (typeof fct[/startx] === 'function') { //check if function then execute it
fct[/startx]();
}
There are several ways so I will summarize them all
function foo(v) {if (v instanceof Function) {/* do something */} };Most performant (no string comparison) and elegant solution - the instanceof operator has been supported in browsers for a very long time, so don't worry - it will work in IE 6.
function foo(v) {if (typeof v === "function") {/* do something */} };disadvantage of
typeof
is that it is susceptible to silent failure, bad, so if you have a typo (e.g. "finction") - in this case the `if` will just return false and you won't know you have an error until later in your code
function isFunction(functionToCheck) { var getType = {}; return functionToCheck && getType.toString.call(functionToCheck) === '[object Function]'; }This has no advantage over solution #1 or #2 but is a lot less readable. An improved version of this is
function isFunction(x) { return Object.prototype.toString.call(x) == '[object Function]'; }but still lot less semantic than solution #1
Source: Stackoverflow.com