How to grep for two words existing on the same line

Question

How do I grep for lines that contain two input words on the line   I m looking for lines that contain both words  how do I do that  I tried pipe like this   grep -c  word1    grep -r  word2  logs   It just stucks after the first pipe command   Why

User · Answer

Use grep   grep -wE  string1 String2       file name   Or you can use   echo string   grep -wE  string1 String2

User · Answer

you could use awk  like this     cat  lt yourFile gt    awk   word1   amp  amp   word2     Order is not important  So if you have a file and     a file named   file1 contains   word1 is in this file as well as word2 word2 is in this file as well as word1 word4 is in this file as well as word1 word5 is in this file as well as word2   then     tmp  cat file1  awk   word1   amp  amp   word2     will result in   word1 is in this file as well as word2 word2 is in this file as well as word1   yes  awk is slower

User · Answer

Why do you pass -c  That will just show the number of matches  Similarly  there is no reason to use -r  I suggest you read man grep   To grep for 2 words existing on the same line  simply do   grep  word1  FILE   grep  word2    grep  word1  FILE will print all lines that have word1 in them from FILE  and then grep  word2  will print the lines that have word2 in them  Hence  if you combine these using a pipe  it will show lines containing both word1 and word2   If you just want a count of how many lines had the 2 words on the same line  do   grep  word1  FILE   grep -c  word2    Also  to address your question why does it get stuck   in grep -c  word1   you did not specify a file  Therefore  grep expects input from stdin  which is why it seems to hang  You can press Ctrl D to send an EOF  end-of-file  so that it quits

User · Answer

git grep  Here is the syntax using git grep combining multiple patterns using Boolean expressions   git grep -e pattern1 --and -e pattern2 --and -e pattern3   The above command will print lines matching all the patterns at once   If the files aren t under version control  add --no-index param      Search files in the current directory that is not managed by Git    Check man git-grep for help   See also    How to use grep to match string1 AND string2  Check if all of multiple strings or regexes exist in a file  How to run grep with multiple AND patterns  For multiple patterns stored in the file  see  Match all patterns from file at once

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Prescription  One simple rewrite of the command in the question is   grep  word1  logs   grep  word2    The first grep finds lines with  word1  from the file  logs  and then feeds those into the second grep which looks for lines containing  word2    However  it isn t necessary to use two commands like that   You could use extended grep  grep -E or egrep    grep -E  word1  word2 word2  word1  logs   If you know that  word1  will precede  word2  on the line  you don t even need the alternatives and regular grep would do   grep  word1  word2  logs   The  one command  variants have the advantage that there is only one process running  and so the lines containing  word1  do not have to be passed via a pipe to the second process   How much this matters depends on how big the data file is and how many lines match  word1    If the file is small  performance isn t likely to be an issue and running two commands is fine   If the file is big but only a few lines contain  word1   there isn t going to be much data passed on the pipe and using two command is fine   However  if the file is huge and  word1  occurs frequently  then you may be passing significant data down the pipe where a single command avoids that overhead   Against that  the regex is more complex  you might need to benchmark it to find out what s best     but only if performance really matters   If you run two commands  you should aim to select the less frequently occurring word in the first grep to minimize the amount of data processed by the second   Diagnosis  The initial script is   grep -c  word1    grep -r  word2  logs   This is an odd command sequence   The first grep is going to count the number of occurrences of  word1  on its standard input  and print that number on its standard output   Until you indicate EOF  e g  by typing Control-D   it will sit there  waiting for you to type something   The second grep does a recursive search for  word2  in the files underneath directory logs  or  if it is a file  in the file logs    Or  in my case  it will fail since there s neither a file nor a directory called logs where I m running the pipeline   Note that the second grep doesn t read its standard input at all  so the pipe is superfluous   With Bash  the parent shell waits until all the processes in the pipeline have exited  so it sits around waiting for the grep -c to finish  which it won t do until you indicate EOF   Hence  your code seems to get stuck   With Heirloom Shell  the second grep completes and exits  and the shell prompts again   Now you have two processes running  the first grep and the shell  and they are both trying to read from the keyboard  and it is not determinate which one gets any given line of input  or any given EOF indication    Note that even if you typed data as input to the first grep  you would only get any lines that contain  word2  shown on the output     Footnote   At one time  the answer used   grep -E  word1  word2 word2  word1       grep  word1  word2         This triggered the comments below

User · Answer

The main issue is that you haven t supplied the first grep with any input  You will need to reorder your command something like  grep  word1  logs   grep  word2    If you want to count the occurences  then put a  -c  on the second grep

User · Answer

You cat try with below command  cat log grep -e word1 -e word2

[grep] How to grep for two words existing on the same line?

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