Is there a short way to find the longest string in a string array?
Something like arr.Max(x => x.Length);
?
This question is related to
javascript
Using Array.prototype - (sort is similar to what was posted by @katsPaugh and @deceze while I was doing a fiddle)
var arr = [
"2 --",
"3 ---",
"4 ----",
"1 -",
"5 -----"
];
Array.prototype.longest=function() {
return this.sort(
function(a,b) {
if (a.length > b.length) return -1;
if (a.length < b.length) return 1;
return 0
}
)[0];
}
alert(arr.longest());
I was inspired of Jason's function and made a little improvements to it and got as a result rather fast finder:
function timo_longest(a) {
var c = 0, d = 0, l = 0, i = a.length;
if (i) while (i--) {
d = a[i].length;
if (d > c) {
l = i; c = d;
}
}
return a[l];
}
arr=["First", "Second", "Third"];
var longest = timo_longest(arr);
Speed results: http://jsperf.com/longest-string-in-array/7
I provide a functional+recursive approach. See comments to understand how it works:
const input1 = ['a', 'aa', 'aaa']_x000D_
const input2 = ['asdf', 'qwer', 'zxcv']_x000D_
const input3 = ['asdfasdf fdasdf a sd f', ' asdfsdf', 'asdfasdfds', 'asdfsdf', 'asdfsdaf']_x000D_
const input4 = ['ddd', 'dddddddd', 'dddd', 'ddddd', 'ddd', 'dd', 'd', 'd', 'dddddddddddd']_x000D_
_x000D_
// Outputs which words has the greater length_x000D_
// greatestWord :: String -> String -> String_x000D_
const greatestWord = x => y => _x000D_
x.length > y.length ? x : y_x000D_
_x000D_
// Recursively outputs the first longest word in a series_x000D_
// longestRec :: String -> [String] -> String_x000D_
const longestRec = longestWord => ([ nextWord, ...words ]) =>_x000D_
// ^^^^^^^^^^^^_x000D_
// Destructuring lets us get the next word, and remaining ones!_x000D_
nextWord // <-- If next word is undefined, then it won't recurse._x000D_
? longestRec (greatestWord (nextWord) (longestWord)) (words) _x000D_
: longestWord_x000D_
_x000D_
_x000D_
// Outputs the first longest word in a series_x000D_
// longest :: [String] -> String_x000D_
const longest = longestRec ('')_x000D_
_x000D_
const output1 = longest (input1)_x000D_
const output2 = longest (input2) _x000D_
const output3 = longest (input3)_x000D_
const output4 = longest (input4)_x000D_
_x000D_
console.log ('output1: ', output1)_x000D_
console.log ('output2: ', output2)_x000D_
console.log ('output3: ', output3)_x000D_
console.log ('output4: ', output4)
_x000D_
Came here for the solution, but could not understand much, posting my version;
const getLongestStr = (longestStr, str) => {
return longestStr.length > str.length ? longestStr : str;
}
var input = ['ali', 'Shahenshah', 'naqvi', 'hm'];
var longest = input.reduce(getLongestStr, "")
function allLongestStrings(array) {
const newArr=[];
let temp = Math.max(...(array.map(el => el.length)));
array.forEach(item => {
if(temp == item.length){
newArr.push(item);
}
});
return newArr;
}
Modern browsers support a for...of
loop. The fastest and shortest way to solve this problem in Chrome, Safari, Edge, and Firefox is also the clearest:
let largest = '';
for (let item of arr) {
if (item.length > largest.length) largest = item
}
In IE, you can use Array.forEach
; that's still faster and clearer than sorting or reducing the array.
var largest = '';
arr.forEach(function(item) {
if (item.length > largest.length) largest = item
});
A new answer to an old question: in ES6 you can do shorter:
Math.max(...(x.map(el => el.length)));
function findLongestWord(str) {
str = str.split(" ");
var sorted = str.sort(function(prev,current){
return prev.length - current.length;
});
var index = sorted.length;
str = sorted[index-1];
return str;
}
findLongestWord("The quick brown fox jumped over the lazy dog");
var longest = (arr) => {
let sum = 0
arr.map((e) => {
sum = e.length > sum ? e.length : sum
})
return sum
}
it can be work
var arr = [ 'fdgdfgdfg', 'gdfgf', 'gdfgdfhawsdgd', 'gdf', 'gdfhdfhjurvweadsd' ];
arr.sort(function (a, b) { return b.length - a.length })[0];
I would do something like this
var arr = [
'first item',
'second item is longer than the third one',
'third longish item'
];
var lgth = 0;
var longest;
for (var i = 0; i < arr.length; i++) {
if (arr[i].length > lgth) {
var lgth = arr[i].length;
longest = arr[i];
}
}
console.log(longest);
_x000D_
If your string is already split into an array, you'll not need the split part.
function findLongestWord(str) {
str = str.split(' ');
var longest = 0;
for(var i = 0; i < str.length; i++) {
if(str[i].length >= longest) {
longest = str[i].length;
}
}
return longest;
}
findLongestWord("The quick brown fox jumped over the lazy dog");
In ES6 this could be accomplished with a reduce()
call in O(n)
complexity as opposed to solutions using sort()
which is O(nlogn)
:
const getLongestText = (arr) => arr.reduce(_x000D_
(savedText, text) => (text.length > savedText.length ? text : savedText),_x000D_
'',_x000D_
);_x000D_
_x000D_
console.log(getLongestText(['word', 'even-longer-word', 'long-word']))
_x000D_
I see the shortest solution
function findLong(s){
return Math.max.apply(null, s.split(' ').map(w => w.length));
}
With ES6 supported also duplicate string
var allLongestStrings = arrayOfStrings => {
let maxLng = Math.max(...arrayOfStrings.map( elem => elem.length))
return arrayOfStrings.filter(elem => elem.length === maxLng)
}
let arrayOfStrings = ["aba", "aa", "ad", "vcd","aba"]
console.log(allLongestStrings(arrayOfStrings))
Maybe not the fastest, but certainly pretty readable:
function findLongestWord(array) {
var longestWord = "";
array.forEach(function(word) {
if(word.length > longestWord.length) {
longestWord = word;
}
});
return longestWord;
}
var word = findLongestWord(["The","quick","brown", "fox", "jumped", "over", "the", "lazy", "dog"]);
console.log(word); // result is "jumped"
The array function forEach has been supported since IE9+.
In case you expect more than one maximum this will work:
_.maxBy(Object.entries(_.groupBy(x, y => y.length)), y => parseInt(y[0]))[1]
It uses lodash and returns an array.
This is my simple solution
var arr = ["you", "are", "the", "love", "of", "my", "life"];
var sorted = arr.sort(function (a, b){
return b.length - a.length;
});
console.log(sorted[0])
I will do something like this:
function findLongestWord(str) {
var array = str.split(" ");
var maxLength=array[0].length;
for(var i=0; i < array.length; i++ ) {
if(array[i].length > maxLength) maxLength = array[i].length}
return maxLength;}
findLongestWord("What if we try a super-long word such as otorhinolaryngology");
var array = ["hello","falsey","undefined"];
var findLongestWord = function(array){
var longest = array.reduce(function(a,b){
return (a.length > b.length) ? a : b;
});
return longest;
}
findLongestWord(array);
Source: Stackoverflow.com