How can I use grep to show just filenames on Linux

Question

How can I use grep to show just file-names  no in-line matches  on Linux   I am usually using something like   find   -iname   php  -exec grep -H myString         How can I just get the file-names  with paths   but without the matches  Do I have to use xargs  I didn t see a way to do this on my grep man page

User · Answer

From the grep 1  man page      -l  --files-with-matches           Suppress  normal  output   instead  print the name of each input           file from which output would normally have  been  printed    The           scanning  will  stop  on  the  first match    -l is specified by           POSIX

User · Answer

Your question How can I just get the file-names  with paths   Your syntax example find   -iname   php  -exec grep -H myString        My Command suggestion  sudo find  home -name   php   The output from this command on my Linux OS      compose-sample-3 html mail contact me php   As you require the filename with path  enjoy

User · Answer

The standard option grep -l  that is a lowercase L  could do this   From the Unix standard   -l      The letter ell   Write only the names of files containing selected     lines to standard output  Pathnames are written once per file searched      If the standard input is searched  a pathname of  standard input  will     be written  in the POSIX locale  In other locales  standard input may be     replaced by something more appropriate in those locales    You also do not need -H in this case

User · Answer

For a simple file search you could use grep s -l and -r options   grep -rl  mystring    All the search is done by grep  Of course  if you need to select files on some other parameter  find is the correct solution   find   -iname    php  -execdir grep -l  mystring         The execdir option builds each grep command per each directory  and concatenates filenames into only one command

[linux] How can I use grep to show just filenames on Linux?

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