Returning the function name without ()
returns a reference to the function, which can be assigned as you've done with var s = a()
. s
now contains a reference to the function b()
, and calling s()
is functionally equivalent to calling b()
.
// Return a reference to the function b().
// In your example, the reference is assigned to var s
return b;
Calling the function with ()
in a return statement executes the function, and returns whatever value was returned by the function. It is similar to calling var x = b();
, but instead of assigning the return value of b()
you are returning it from the calling function a()
. If the function b()
itself does not return a value, the call returns undefined
after whatever other work is done by b()
.
// Execute function b() and return its value
return b();
// If b() has no return value, this is equivalent to calling b(), followed by
// return undefined;