I have the following html:
<a href="#" id="#1" class="pagerlink" >link</a>
<a href="#" id="#3" class="pagerlink" >link</a>
<a href="#" id="#2" class="pagerlink" >link</a>
/*etc.... */
and the following jQuery script:
$(document).ready(function() {
var $container = $('.gallery_r').cycle({
fx: 'scrollHorz',
speed: 500,
timeout: 0
});
$('a.pagerlink').click(function() {
var id = $(this).attr('id');
$container.cycle(id);
return false;
});
});
the 'pagerlink' links control are to jQuery Cycle slideshow. If I swap this line:
$container.cycle(id);
for this
$container.cycle(7);
it works... (obviously only navigating to slide number 7). So, my question is how can I pick up the ID of the link being clicked and pass it into that line?
Thanks in advance!
This question is related to
jquery
jquery-cycle
First off you can't have just a number for your id unless you are using the HTML5 DOCTYPE. Secondly, you need to either remove the # in each id or replace it with this:
$container.cycle(id.replace('#',''));
@Adam Just add a function using onClick="getId()"
function getId(){console.log(this.event.target.id)}
You just need to remove the hash from the beginning:
$('a.pagerlink').click(function() {
var id = $(this).attr('id').substring(1);
$container.cycle(id);
return false;
});
Your id will be passed through as #1, #2 etc. However, # is not valid as an ID (CSS selectors prefix IDs with #).
Source: Stackoverflow.com