How to get just the parent directory name of a specific file

Question

How to get ddd from the path name where the test java resides   File file   new File  C  aaa bbb ccc ddd test java

User · Answer

For Kotlin    fun getFolderName                              val uri  Uri             val cursor  Cursor                   uri   MediaStore Audio Media EXTERNAL CONTENT URI             val projection   arrayOf MediaStore Audio AudioColumns DATA              cursor   requireActivity   contentResolver query uri  projection  null  null  null              if  cursor    null                    column index data   cursor getColumnIndexOrThrow MediaStore Audio AudioColumns DATA                                         while  cursor   moveToNext                           absolutePathOfImage   cursor getString column index data                            val fileName  String   File absolutePathOfImage  parentFile name

User · Answer

File file   new File  C  aaa bbb ccc ddd test java    File curentPath   new File file getParent       get current path  C  aaa bbb ccc ddd   String currentFolder  currentPath getName   toString      get name of file to string  ddd    if you need to append folder  ddd  by another path use   String currentFolder        currentPath getName   toString

User · Answer

Use File s getParentFile   method and String lastIndexOf   to retrieve just the immediate parent directory    Mark s comment is a better solution thanlastIndexOf     file getParentFile   getName      These solutions only works if the file has a parent file  e g   created via one of the file constructors taking a parent File   When getParentFile   is null you ll need to resort to using lastIndexOf  or use something like Apache Commons  FileNameUtils getFullPath     FilenameUtils getFullPathNoEndSeparator file getAbsolutePath       gt  C  aaa bbb ccc ddd   There are several variants to retain drop the prefix and trailing separator  You can either use the same FilenameUtils class to grab the name from the result  use lastIndexOf  etc

User · Answer

From java 7 I would prefer to use Path  You only need to put path into   Path dddDirectoryPath   Paths get  C  aaa bbb ccc ddd test java      and create some get method   public String getLastDirectoryName Path directoryPath       int nameCount   directoryPath getNameCount       return directoryPath getName nameCount - 1

User · Answer

File f   new File  C  aaa bbb ccc ddd test java    System out println f getParentFile   getName      f getParentFile   can be null  so you should check it

User · Answer

In Java 7 you have the new Paths api  The modern and cleanest solution is  Paths get  quot C  aaa bbb ccc ddd test java quot   getParent   getFileName     Result would be  C  aaa bbb ccc ddd

User · Answer

Use below   File file   new File  file path    String parentPath   file getAbsoluteFile   getParent

User · Answer

get the parentfolder name     File file   new File  System getProperty  user dir                String parentPath   file getParentFile   getName

User · Answer

If you have just String path and don t want to create new File object you can use something like   public static String getParentDirPath String fileOrDirPath        boolean endsWithSlash   fileOrDirPath endsWith File separator       return fileOrDirPath substring 0  fileOrDirPath lastIndexOf File separatorChar               endsWithSlash   fileOrDirPath length   - 2   fileOrDirPath length   - 1

User · Answer

In Groovy   There is no need to create a File instance to parse the string in groovy  It can be done as follows   String path    C  aaa bbb ccc ddd test java  path split      -2      this will return ddd   The split will create the array  C   aaa  bbb  ccc  ddd  test java  and index -2 will point to entry before the last one  which in this case is ddd

[java] How to get just the parent directory name of a specific file

Examples related to java

Examples related to groovy

Examples related to java-io