Alter and Assign Object Without Side Effects

Question

I currently have the following code   var myArray       var myElement       id  0    value  0    myElement id   0  myElement value   1  myArray 0    myElement   myElement id   2  myElement value   3  myArray 1    myElement    The problem is that when I change the value of id and value for my second element  the values also change in the first element  Is there a way that I can keep adding new elements without it changing the value of the previously inserted values in the array

User · Accepted Answer

Try this instead   var myArray        myArray push   id  0  value  1     myArray push   id  2  value  3       or will this not work for your situation

User · Answer

If you re using jQuery  you can use extend  myElement id  0  myElement value 1  myArray 0      extend     myElement    myElement id   2  myElement value   3  myArray 1      extend     myElement

User · Answer

Objects are passed by reference   To create a new object  I follow this approach      Template code for object creation  function myElement id  value        this id   id      this value   value    var myArray          instantiate myEle var myEle   new myElement 0  0     store myEle myArray 0    myEle     Now create a new object  amp  store it myEle   new myElement 0  1   myArray 1    myEle

User · Answer

You will have the same object two times in your array  because object values are passed by reference  You have to create a new object like this   myElement id   244  myElement value   3556  myArray 0      extend     myElement     for shallow copy or myArray 0      extend true      myElement      for deep copy   or  myArray push   id  24  value  246

User · Answer

That s because object values are passed by reference  You can clone the object like this   var myArray       var myElement       id  0    value  0    myElement id  0  myElement value 1  myArray 0    myElement   var obj       obj   clone myElement   obj id   2  obj value   3    myArray 1    obj   function clone obj     if obj    null    typeof obj      object       return obj     var temp   new obj constructor       for var key in obj      temp key    clone obj key       return temp         console log myArray 0    console log myArray 1      Result    - id  0  - value  1  - id  2  - value  3

User · Answer

This is a textbook case for a constructor function   var myArray        function myElement id  value       this id   id     this value   value    myArray 0    new myElement 0 1  myArray 1    new myElement 2 3     or myArray push new myElement 1  1

User · Answer

You either need to keep creating new objects  or clone the existing one  See What is the most efficient way to deep clone an object in JavaScript  for how to clone

[javascript] Alter and Assign Object Without Side Effects

Examples related to javascript