I have situation, when click on button opens the new browser window with search results.
Is there any way to connect and focus to new opened browser window?
And work with it, then return back to original(first) window.
This question is related to
java
selenium
selenium-webdriver
webdriver
new-window
So the problem with a lot of these solutions is you're assuming the window appears instantly (nothing happens instantly, and things happen significantly less instantly in IE). Also you're assuming that there will only be one window prior to clicking the element, which is not always the case. Also IE will not return the window handles in a predictable order. So I would do the following.
public String clickAndSwitchWindow(WebElement elementToClick, Duration
timeToWaitForWindowToAppear) {
Set<String> priorHandles = _driver.getWindowHandles();
elementToClick.click();
try {
new WebDriverWait(_driver,
timeToWaitForWindowToAppear.getSeconds()).until(
d -> {
Set<String> newHandles = d.getWindowHandles();
if (newHandles.size() > priorHandles.size()) {
for (String newHandle : newHandles) {
if (!priorHandles.contains(newHandle)) {
d.switchTo().window(newHandle);
return true;
}
}
return false;
} else {
return false;
}
});
} catch (Exception e) {
Logging.log_AndFail("Encountered error while switching to new window after clicking element " + elementToClick.toString()
+ " seeing error: \n" + e.getMessage());
}
return _driver.getWindowHandle();
}
Surya, your way won't work, because of two reasons:
Just to add to the content ...
To go back to the main window(default window) .
use driver.switchTo().defaultContent();
This script helps you to switch over from a Parent window to a Child window and back cntrl to Parent window
String parentWindow = driver.getWindowHandle();
Set<String> handles = driver.getWindowHandles();
for(String windowHandle : handles)
{
if(!windowHandle.equals(parentWindow))
{
driver.switchTo().window(windowHandle);
<!--Perform your operation here for new window-->
driver.close(); //closing child window
driver.switchTo().window(parentWindow); //cntrl to parent window
}
}
Source: Selenium WebDriver windows switching issue in Internet Explorer 8-10
For my case, IE began detecting new window handles after the registry edit.
Tab Process Growth : Sets the rate at which IE creates New Tab processes.
The "Max-Number" algorithm: This specifies the maximum number of tab processes that may be executed for a single isolation session for a single frame process at a specific mandatory integrity level (MIC). Relative values are:
- TabProcGrowth=0 : tabs and frames run within the same process; frames are not unified across MIC levels.
- TabProcGrowth =1: all tabs for a given frame process run in a single tab process for a given MIC level.
Source: Opening a New Tab may launch a New Process with Internet Explorer 8.0
Browser: IE11 x64 (Zoom: 100%)
OS: Windows 7 x64
Selenium: 3.5.1
WebDriver: IEDriverServer x64 3.5.1
public static String openWindow(WebDriver driver, By by) throws IOException {
String parentHandle = driver.getWindowHandle(); // Save parent window
WebElement clickableElement = driver.findElement(by);
clickableElement.click(); // Open child window
WebDriverWait wait = new WebDriverWait(driver, 10); // Timeout in 10s
boolean isChildWindowOpen = wait.until(ExpectedConditions.numberOfWindowsToBe(2));
if (isChildWindowOpen) {
Set<String> handles = driver.getWindowHandles();
// Switch to child window
for (String handle : handles) {
driver.switchTo().window(handle);
if (!parentHandle.equals(handle)) {
break;
}
}
driver.manage().window().maximize();
}
return parentHandle; // Returns parent window if need to switch back
}
/* How to use method */
String parentHandle = Selenium.openWindow(driver, by);
// Do things in child window
driver.close();
// Return to parent window
driver.switchTo().window(parentHandle);
The above code includes an if-check to make sure you are not switching to the parent window as Set<T>
has no guaranteed ordering in Java. WebDriverWait
appears to increase the chance of success as supported by below statement.
The browser may take time to acknowledge the new window, and you may be falling into your switchTo() loop before the popup window appears.
You automatically assume that the last window returned by getWindowHandles() will be the last one opened. That's not necessarily true, as they are not guaranteed to be returned in any order.
Source: Unable to handle a popup in IE,control is not transferring to popup window
If you have more then one browser (using java 8)
import java.util.HashSet;
import java.util.List;
import java.util.Set;
import java.util.stream.Collectors;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.firefox.FirefoxDriver;
public class TestLink {
private static Set<String> windows;
public static void main(String[] args) {
WebDriver driver = new FirefoxDriver();
driver.get("file:///C:/Users/radler/Desktop/myLink.html");
setWindows(driver);
driver.findElement(By.xpath("//body/a")).click();
// get new window
String newWindow = getWindow(driver);
driver.switchTo().window(newWindow);
// Perform the actions on new window
String text = driver.findElement(By.cssSelector(".active")).getText();
System.out.println(text);
driver.close();
// Switch back
driver.switchTo().window(windows.iterator().next());
driver.findElement(By.xpath("//body/a")).click();
}
private static void setWindows(WebDriver driver) {
windows = new HashSet<String>();
driver.getWindowHandles().stream().forEach(n -> windows.add(n));
}
private static String getWindow(WebDriver driver) {
List<String> newWindow = driver.getWindowHandles().stream()
.filter(n -> windows.contains(n) == false).collect(Collectors.toList());
System.out.println(newWindow.get(0));
return newWindow.get(0);
}
}
You could use:
driver.SwitchTo().Window(WindowName);
Where WindowName is a string representing the name of the window you want to switch focus to. Call this function again with the name of the original window to get back to it when you are done.
I use iterator and a while loop to store the various window handles and then switch back and forth.
//Click your link
driver.findElement(By.xpath("xpath")).click();
//Get all the window handles in a set
Set <String> handles =driver.getWindowHandles();
Iterator<String> it = handles.iterator();
//iterate through your windows
while (it.hasNext()){
String parent = it.next();
String newwin = it.next();
driver.switchTo().window(newwin);
//perform actions on new window
driver.close();
driver.switchTo().window(parent);
}
main you can do :
String mainTab = page.goToNewTab ();
//do what you want
page.backToMainPage(mainTab);
What you need to have in order to use the main
private static Set<String> windows;
//get all open windows
//return current window
public String initWindows() {
windows = new HashSet<String>();
driver.getWindowHandles().stream().forEach(n -> windows.add(n));
return driver.getWindowHandle();
}
public String getNewWindow() {
List<String> newWindow = driver.getWindowHandles().stream().filter(n -> windows.contains(n) == false)
.collect(Collectors.toList());
logger.info(newWindow.get(0));
return newWindow.get(0);
}
public String goToNewTab() {
String startWindow = driver.initWindows();
driver.findElement(By.cssSelector("XX")).click();
String newWindow = driver.getNewWindow();
driver.switchTo().window(newWindow);
return startWindow;
}
public void backToMainPage(String startWindow) {
driver.close();
driver.switchTo().window(startWindow);
}
Source: Stackoverflow.com