If the undefined's are implicit then you can do:
var len = 0;
for (var i in arr) { len++ };
undefined's are implicit if you don't set them explicitly
//both are a[0] and a[3] are explicit undefined
var arr = [undefined, 1, 2, undefined];
arr[6] = 3;
//now arr[4] and arr[5] are implicit undefined
delete arr[1]
//now arr[1] is implicit undefined
arr[2] = undefined
//now arr[2] is explicit undefined