I want to convert the following (working) curl snippet to a RestTemplate call:
curl -i -X POST -d "[email protected]" https://app.example.com/hr/email
How do I pass the email parameter correctly? The following code results in a 404 Not Found response:
String url = "https://app.example.com/hr/email";
Map<String, String> params = new HashMap<String, String>();
params.put("email", "[email protected]");
RestTemplate restTemplate = new RestTemplate();
ResponseEntity<String> response = restTemplate.postForEntity( url, params, String.class );
I've tried to formulate the correct call in PostMan, and I can get it working correctly by specifying the email parameter as a "form-data" parameter in the body. What is the correct way to achieve this functionality in a RestTemplate?
This question is related to
java
spring
rest
resttemplate
The POST method should be sent along the HTTP request object. And the request may contain either of HTTP header or HTTP body or both.
Hence let's create an HTTP entity and send the headers and parameter in body.
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
MultiValueMap<String, String> map= new LinkedMultiValueMap<String, String>();
map.add("email", "[email protected]");
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<MultiValueMap<String, String>>(map, headers);
ResponseEntity<String> response = restTemplate.postForEntity( url, request , String.class );
here is the full program to make a POST rest call using spring's RestTemplate.
import java.util.HashMap;
import java.util.Map;
import org.springframework.http.HttpEntity;
import org.springframework.http.ResponseEntity;
import org.springframework.util.LinkedMultiValueMap;
import org.springframework.util.MultiValueMap;
import org.springframework.web.client.RestTemplate;
import com.ituple.common.dto.ServiceResponse;
public class PostRequestMain {
public static void main(String[] args) {
// TODO Auto-generated method stub
MultiValueMap<String, String> headers = new LinkedMultiValueMap<String, String>();
Map map = new HashMap<String, String>();
map.put("Content-Type", "application/json");
headers.setAll(map);
Map req_payload = new HashMap();
req_payload.put("name", "piyush");
HttpEntity<?> request = new HttpEntity<>(req_payload, headers);
String url = "http://localhost:8080/xxx/xxx/";
ResponseEntity<?> response = new RestTemplate().postForEntity(url, request, String.class);
ServiceResponse entityResponse = (ServiceResponse) response.getBody();
System.out.println(entityResponse.getData());
}
}
Your url String needs variable markers for the map you pass to work, like:
String url = "https://app.example.com/hr/email?{email}";
Or you could explicitly code the query params into the String to begin with and not have to pass the map at all, like:
String url = "https://app.example.com/hr/[email protected]";
How to POST mixed data: File, String[], String in one request.
You can use only what you need.
private String doPOST(File file, String[] array, String name) {
RestTemplate restTemplate = new RestTemplate(true);
//add file
LinkedMultiValueMap<String, Object> params = new LinkedMultiValueMap<>();
params.add("file", new FileSystemResource(file));
//add array
UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl("https://my_url");
for (String item : array) {
builder.queryParam("array", item);
}
//add some String
builder.queryParam("name", name);
//another staff
String result = "";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> requestEntity =
new HttpEntity<>(params, headers);
ResponseEntity<String> responseEntity = restTemplate.exchange(
builder.build().encode().toUri(),
HttpMethod.POST,
requestEntity,
String.class);
HttpStatus statusCode = responseEntity.getStatusCode();
if (statusCode == HttpStatus.ACCEPTED) {
result = responseEntity.getBody();
}
return result;
}
The POST request will have File in its Body and next structure:
POST https://my_url?array=your_value1&array=your_value2&name=bob
Source: Stackoverflow.com