Using grep to search for a string that has a dot in it

Question

I am trying to search for a string 0 49  with dot  using the command  grep -r  0 49      But what happening is that I am also getting unwanted results which contains the string such as 0449  0949 etc   The thing is linux considering dot    as any character and bringing out all the results  But I want to get the result only for  0 49

User · Answer

Escape dot  Sample command will be   grep  0  00

User · Answer

You can also use        grep -r  0   49

User · Answer

grep uses regexes    means  any character  in a regex   If you want a literal string  use grep -F  fgrep  or escape the   to      Don t forget to wrap your string in double quotes  Or else you should use      So  your command would need to be   grep -r  0  49      or   grep -r 0   49     or  grep -Fr 0 49

User · Answer

Just escape the    grep -r  0  49

User · Answer

You can also search with -- option which basically ignores all the special characters and it won t be interpreted by grep     cat foo  grep --  0  49

User · Answer

You can escape the dot and other special characters using    eg  grep -r  0  49

User · Answer

grep -F -r  0 49    treats 0 49 as a  fixed  string instead of a regular expression  This makes   lose its special meaning

User · Answer

You need to escape the   as  0  49     A   is a regex meta-character to match any character except newline   To match a literal period  you need to escape it

User · Answer

There are so many answers here suggesting to escape the dot with    but I have been running into this issue over and over again     gives me the same result as   However  these two expressions work for me    grep -r 0   49    And    grep -r 0   49    I m using a  quot normal quot  bash shell on Ubuntu and Archlinux  Edit  or  according to comments    grep -r  0  49     Note  the single-quotes doing the difference here

[linux] Using grep to search for a string that has a dot in it

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