[java] Show only two digit after decimal

How to get the double value that is only two digit after decimal point.

for example

if

i=348842.
double i2=i/60000;
tv.setText(String.valueOf(i2));

this code generating 5.81403333.

But I want only 5.81.

So what shoud I do?

i=348842.
double i2=i/60000;
DecimalFormat dtime = new DecimalFormat("#.##"); 
i2= Double.valueOf(dtime.format(time));
v.setText(String.valueOf(i2));

I think the best and simplest solution is (KISS):

double i = 348842;
double i2 = i/60000;
float k = (float) Math.round(i2 * 100) / 100;

Many other answers only do formatting. This approach will return value instead of only print format.

double number1 = 10.123456;
double number2 = (int)(Math.round(number1 * 100))/100.0;
System.out.println(number2);

Here i will demonstrate you that how to make your decimal number short. Here i am going to make it short upto 4 value after decimal.

  double value = 12.3457652133
  value =Double.parseDouble(new DecimalFormat("##.####").format(value));

How about String.format("%.2f", i2)?

First thing that should pop in a developer head while formatting a number into char sequence should be care of such details like do it will be possible to reverse the operation.

And other aspect is providing proper result. So you want to truncate the number or round it.

So before you start you should ask your self, am i interested on the value or not.

To achieve your goal you have multiple options but most of them refer to Format and Formatter, but i just suggest to look in this answer.