How do I programmatically access the value shown in the image below ?
This question is related to
android
serial-number
Build.SERIAL
can be empty or sometimes return a different value (proof 1, proof 2) than what you can see in your device's settings.
If you want a more complete and robust solution, I've compiled every possible solution I could found in a single gist. Here's a simplified version of it :
public static String getSerialNumber() {
String serialNumber;
try {
Class<?> c = Class.forName("android.os.SystemProperties");
Method get = c.getMethod("get", String.class);
serialNumber = (String) get.invoke(c, "gsm.sn1");
if (serialNumber.equals(""))
serialNumber = (String) get.invoke(c, "ril.serialnumber");
if (serialNumber.equals(""))
serialNumber = (String) get.invoke(c, "ro.serialno");
if (serialNumber.equals(""))
serialNumber = (String) get.invoke(c, "sys.serialnumber");
if (serialNumber.equals(""))
serialNumber = Build.SERIAL;
// If none of the methods above worked
if (serialNumber.equals(""))
serialNumber = null;
} catch (Exception e) {
e.printStackTrace();
serialNumber = null;
}
return serialNumber;
}
I try to update the gist regularly whenever I can test on a new device or Android version. Contributions are welcome too.
Until Android 7.1 you will get it with:
Build.SERIAL
On Android 8 (SDK 26) and above, this field will return UNKNOWN
and must be accessed with:
Build.getSerial()
which requires the dangerous permission
android.permission.READ_PHONE_STATE
.
Since Android Q using Build.getSerial()
gets a bit more complicated by requiring:
android.Manifest.permission.READ_PRIVILEGED_PHONE_STATE
(which can only be acquired by system apps), or for the calling package to be the device or profile owner and have the READ_PHONE_STATE
permission. This means most apps won't be able to uses this feature. See the Android Q announcement from Google.
If you just require a unique identifier, it's best to avoid using hardware identifiers as Google continuously tries to make it harder to access them for privacy reasons. You could just generate a UUID.randomUUID().toString();
and save it the first time it needs to be accessed in e.g. shared preferences. Alternatively you could use ANDROID_ID
which is a 8 byte long hex string unique to the device, user and (only Android 8+) app installation. For more info on that topic, see Best practices for unique identifiers.
From Android P, defining the READ_PHONE_STATE permission in AndroidManifest only, will not work. We have to actually request for the permission. Below code works for me:
@RequiresApi(api = Build.VERSION_CODES.P)
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.READ_PHONE_STATE}, 101);
}
}
@RequiresApi(api = Build.VERSION_CODES.O)
@Override
protected void onResume() {
super.onResume();
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return;
}
Log.d(TAG,Build.getSerial());
}
@RequiresApi(api = Build.VERSION_CODES.O)
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
switch (requestCode) {
case 101:
if (grantResults[0] == PackageManager.PERMISSION_GRANTED) {
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return;
}
} else {
//not granted
}
break;
default:
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
}
}
Add this permissions in AndroidManifest.xml
<uses-permission android:name = "android.permission.INTERNET"/>
<uses-permission android:name = "android.permission.READ_PHONE_STATE" />
Hope this helps.
Thank You, MJ
Source: Stackoverflow.com