How do I dynamically assign properties to an object in TypeScript

Question

If I wanted to programatically assign a property to an object in Javascript  I would do it like this   var obj       obj prop    value     But in TypeScript  this generates an error      The property  prop  does not exist on value of type        How am I supposed to assign any new property to an object in TypeScript

User · Answer

Store any new property on any kind of object by typecasting it to 'any':

var extend = <any>myObject;
extend.NewProperty = anotherObject;

Later on you can retrieve it by casting your extended object back to 'any':

var extendedObject = <any>myObject;
var anotherObject = <AnotherObjectType>extendedObject.NewProperty;

User · Answer

Since you cannot do this   obj prop    value     If your TS compiler and your linter does not strict you  you can write this   obj  prop      value     If your TS compiler or linter is strict  another answer would be to typecast   var obj       obj   obj as unknown as   prop  string    obj prop    value

User · Answer

Here is a special version of Object assign  that automatically adjusts the variable type with every property change  No need for additional variables  type assertions  explicit types or object copies   function assign lt T  U gt  target  T  source  U   asserts target is T  amp  U       Object assign target  source     const obj       assign obj    prop1   foo         const obj now has type   prop1  string    obj prop1    string assign obj    prop2  42        const obj now has type   prop1  string  prop2  number    obj prop2    number      const obj    prop1   foo   prop2  42     Note  The sample makes use of TS 3 7 assertion functions  The return type of assign is void  unlike Object assign

User · Answer

It is possible to add a member to an existing object by   widening the type  read  extend specialize the interface  cast the original object to the extended type add the member to the object   interface IEnhancedPromise lt T gt  extends Promise lt T gt        sayHello    void     const p   Promise resolve  Peter     const enhancedPromise   p as IEnhancedPromise lt string gt    enhancedPromise sayHello        gt  enhancedPromise then value   gt  console info  Hello     value        eventually prints  Hello Peter  enhancedPromise sayHello

User · Answer

I tend to put any on the other side i e  var foo IFoo    lt any gt     So something like this is still typesafe    interface IFoo      bar string      baz string      boo string             How I tend to intialize  var foo IFoo    lt any gt      foo bar    asdf   foo baz    boo   foo boo    boo       the following is an error      so you haven t lost type safety foo bar   123     Alternatively you can mark these properties as optional    interface IFoo      bar  string      baz  string      boo  string            Now your simple initialization works var foo IFoo         Try it online

User · Answer

One more option do to that is to access the property as a collection    x000D   x000D  var obj       x000D  obj  prop      value   x000D   x000D   x000D

User · Answer

The best practice is use safe typing  I recommend you   interface customObject extends MyObject      newProp  string     newProp2  number

User · Answer

Simplest will be following   const obj    lt any gt     obj prop1    value   obj prop2    another value

User · Answer

You can add this declaration to silence the warnings   declare var obj  any

User · Answer

The only solution that is fully type-safe is this one  but is a little wordy and forces you to create multiple objects   If you must create an empty object first  then pick one of these two solutions  Keep in mind that every time you use as  you re losing safety   Safer solution  The type of object is safe inside getObject  which means object a will be of type string   undefined  interface Example     a  string    b  number     function getObject       const object  Partial lt Example gt          object a    one     object b   1    return object as Example      Short solution  The type of object is not safe inside getObject  which means object a will be of type string even before its assignment   interface Example     a  string    b  number     function getObject       const object      as Example    object a    one     object b   1    return object

User · Answer

Try this   export interface QueryParams       page   number      limit   number      name   string      sort   string      direction   string     Then use it  const query         name   abc    query page   1

User · Answer

I m surprised that none of the answers reference Object assign since that s the technique I use whenever I think about  composition  in JavaScript   And it works as expected in TypeScript   interface IExisting       userName  string    interface INewStuff       email  string    const existingObject  IExisting         userName   jsmith     const objectWithAllProps  IExisting  amp  INewStuff   Object assign     existingObject        email   jsmith someplace com      console log objectWithAllProps email      jsmith someplace com   Advantages   type safety throughout because you don t need to use the any type at all uses TypeScript s aggregate type  as denoted by the  amp  when declaring the type of objectWithAllProps   which clearly communicates that we re composing a new type on-the-fly  i e  dynamically    Things to be aware of   Object assign has it s own unique aspects  that are well known to most experienced JS devs  that should be considered when writing TypeScript     It can be used in a mutable fashion  or an immutable manner  I demonstrate the immutable way above  which means that existingObject stays untouched and therefore doesn t have an email property  For most functional-style programmers  that s a good thing since the result is the only new change   Object assign works the best when you have flatter objects  If you are combining two nested objects that contain nullable properties  you can end up overwriting truthy values with undefined  If you watch out for the order of the Object assign arguments  you should be fine

User · Answer

Case 1   var car    type   BMW   model   i8   color   white     car  owner      ibrahim      You can add a property    Case 2   var car any    type   BMW   model   i8   color   white     car owner    ibrahim      You can set a property  use any type

User · Answer

Or all in one go     var obj any        obj prop   5

User · Answer

To guarantee that the type is an Object  i e  key-value pairs   use   const obj    x  string   any       obj prop    cool beans

User · Answer

To preserve your previous type  temporary cast your object to any    var obj          lt any gt obj  prop   5    The new dynamic property will only be available when you use the cast     var a   obj prop     gt  Will generate a compiler error   var b     lt any gt obj  prop     gt  Will assign 5 to b with no error

User · Answer

Extending  jmvtrinidad solution for Angular  When working with a already existing typed object  this is how to add new property  let user  User   new User     user as any  otherProperty    hello     user did not lose its type here   Now if you want to use otherProperty in html side  this is what you d need   lt div  ngIf  quot  any user  otherProperty quot  gt                 lt  div gt   Angular compiler treats  any   as a cast to the any type just like in TypeScript when a  lt any gt  or as any cast is used

User · Answer

Index types It is possible to denote obj as any  but that defeats the whole purpose of using typescript  obj      implies obj is an Object  Marking it as any makes no sense  To accomplish the desired consistency an interface could be defined as follows  interface LooseObject        key  string   any    var obj  LooseObject        OR to make it compact  var obj    k  string   any         LooseObject can accept fields with any string as key and any type as value  obj prop    quot value quot   obj prop2   88   The real elegance of this solution is that you can include typesafe fields in the interface  interface MyType       typesafeProp1   number      requiredProp1  string       key  string   any    var obj  MyType   obj     requiredProp1   quot foo quot       valid obj         error   requiredProp1  is missing obj typesafeProp1    quot bar quot     error  typesafeProp1 should be a number  obj prop    quot value quot   obj prop2   88   Record lt Keys Type gt   utility type  Update  August 2020    transang brought this up in comments   Record lt Keys Type gt  is a Utility type in typescript  It is a much cleaner  alternative for key-value pairs where property-names are not known  It s worth noting that Record lt Keys Type gt  is a named alias to   k  Keys   Type  where Keys and Type are generics  IMO  this makes it worth mentioning here  For comparison  var obj    k  string   any         becomes var obj  Record lt string any gt        MyType can now be defined by extending Record type interface MyType extends Record lt string any gt        typesafeProp1   number      requiredProp1  string      While this answers the Original question  the answer here by  GreeneCreations might give another perspective on how to approach the problem

User · Answer

you can use this    this model   Object assign this model    newProp  0

User · Answer

If you are using Typescript  presumably you want to use the type safety  in which case naked Object and  any  are counterindicated   Better to not use Object or     but some named type  or you might be using an API with specific types  which you need extend with your own fields  I ve found this to work   class Given             API specified fields  or maybe it s just Object     interface PropAble extends Given       props   string      you can cast any Given to this and set  props            indicates that the field is optional   let g Given   getTheGivenObject     g as PropAble  props    value for my new field       to avoid constantly casting   let k PropAble   getTheGivenObject    k props    value for props

User · Answer

Although the compiler complains it should still output it as you require  However  this will work   var s       s  prop     true

User · Answer

This solution is useful when your object has Specific Type  Like when obtaining the object to other source   let user  User   new User     user as any  otherProperty    hello     user did not lose its type here

User · Answer

dynamically assign properties to an object in TypeScript   to do that You just need to use typescript interfaces like so   interface IValue       prop1  string      prop2  string     interface IType        code  string   IValue      you can use it like that   var obj  IType       obj  code1            prop1   prop 1 value        prop2   prop 2 value

User · Answer

You can create new object based on the old object using the spread operator  interface MyObject       prop1  string     const myObj  MyObject         prop1   foo      const newObj            myObj      prop2   bar      console log newObj prop2       bar    TypeScript will infer all the fields of the original object and VSCode will do autocompletion  etc

[typescript] How do I dynamically assign properties to an object in TypeScript?

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