You can use the instanceof operator for this. From MDN:
The instanceof operator tests whether the prototype property of a constructor appears anywhere in the prototype chain of an object.
If you don't know what prototypes and prototype chains are I highly recommend looking it up. Also here is a JS (TS works similar in this respect) example which might clarify the concept:
class Animal {_x000D_
name;_x000D_
_x000D_
constructor(name) {_x000D_
this.name = name;_x000D_
}_x000D_
}_x000D_
_x000D_
const animal = new Animal('fluffy');_x000D_
_x000D_
// true because Animal in on the prototype chain of animal_x000D_
console.log(animal instanceof Animal); // true_x000D_
// Proof that Animal is on the prototype chain_x000D_
console.log(Object.getPrototypeOf(animal) === Animal.prototype); // true_x000D_
_x000D_
// true because Object in on the prototype chain of animal_x000D_
console.log(animal instanceof Object); _x000D_
// Proof that Object is on the prototype chain_x000D_
console.log(Object.getPrototypeOf(Animal.prototype) === Object.prototype); // true_x000D_
_x000D_
console.log(animal instanceof Function); // false, Function not on prototype chain_x000D_
_x000D_
The prototype chain in this example is:
animal > Animal.prototype > Object.prototype