Remove special symbols and extra spaces and replace with underscore using the replace method

Question

I want to remove all special characters and spaces from a string and replace with an underscore  The string is      var str    hello world  amp  hello universe     I have this now which replaces only spaces         str replace   s g          The result I get is hello world  amp  hello universe  but I would like to remove the special symbols as well   I tried this str replace    a-zA-Z0-9  s g       but this does not help

User · Answer

It was not asked precisely to remove accent (only special characters), but I needed to.

The solutions givens here works but they don’t remove accent: é, è, etc.

So, before doing epascarello’s solution, you can also do:

_x000D_

var newString = "développeur & intégrateur";_x000D_
_x000D_
newString = replaceAccents(newString);_x000D_
newString = newString.replace(/[^A-Z0-9]+/ig, "_");_x000D_
alert(newString);_x000D_
_x000D_
/**_x000D_
 * Replaces all accented chars with regular ones_x000D_
 */_x000D_
function replaceAccents(str) {_x000D_
  // Verifies if the String has accents and replace them_x000D_
  if (str.search(/[\xC0-\xFF]/g) > -1) {_x000D_
    str = str_x000D_
      .replace(/[\xC0-\xC5]/g, "A")_x000D_
      .replace(/[\xC6]/g, "AE")_x000D_
      .replace(/[\xC7]/g, "C")_x000D_
      .replace(/[\xC8-\xCB]/g, "E")_x000D_
      .replace(/[\xCC-\xCF]/g, "I")_x000D_
      .replace(/[\xD0]/g, "D")_x000D_
      .replace(/[\xD1]/g, "N")_x000D_
      .replace(/[\xD2-\xD6\xD8]/g, "O")_x000D_
      .replace(/[\xD9-\xDC]/g, "U")_x000D_
      .replace(/[\xDD]/g, "Y")_x000D_
      .replace(/[\xDE]/g, "P")_x000D_
      .replace(/[\xE0-\xE5]/g, "a")_x000D_
      .replace(/[\xE6]/g, "ae")_x000D_
      .replace(/[\xE7]/g, "c")_x000D_
      .replace(/[\xE8-\xEB]/g, "e")_x000D_
      .replace(/[\xEC-\xEF]/g, "i")_x000D_
      .replace(/[\xF1]/g, "n")_x000D_
      .replace(/[\xF2-\xF6\xF8]/g, "o")_x000D_
      .replace(/[\xF9-\xFC]/g, "u")_x000D_
      .replace(/[\xFE]/g, "p")_x000D_
      .replace(/[\xFD\xFF]/g, "y");_x000D_
  }_x000D_
_x000D_
  return str;_x000D_
}

_x000D_

Source: https://gist.github.com/jonlabelle/5375315

User · Answer

Remove the  s from your new regex and it should work - whitespace is already included in  anything but alphanumerics    Note that you may want to add a   after the   so you don t get sequences of more than one underscore  You can also chain onto  replace          g     to trim off underscores at the start or end of the string

User · Answer

var str    hello world  amp  hello universe   In order to replace both Spaces and Symbols in one shot  we can use the below regex code   str replaceAll    W        Note   W -  represents Not Words  includes spaces special characters      -  one or many matches  Try it

User · Answer

If you have a text as   var sampleText                   TESTED             amp      amp  amp       XYZ   To replace all special character         amp      amp  amp          without replacing the characters including umlaut   Use below regex  sampleText   sampleText replace            amp      -         lt         s  gi       OUTPUT   sampleText                    TESTED                           XYZ   This would replace all with an underscore which is provided as second argument to the replace function You can add whatever you want as per your requirement

User · Answer

Your regular expression   a-zA-Z0-9  s g says match any character that is not a number or letter followed by a space   Remove the  s and you should get what you are after if you want a   for every special character   var newString   str replace    A-Z0-9  ig          That will result in hello world   hello universe  If you want it to be single underscores use a   to match multiple  var newString   str replace    A-Z0-9   ig          That will result in hello world hello universe

[javascript] Remove special symbols and extra spaces and replace with underscore using the replace method

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