How can I create an object based on an interface file definition in TypeScript

Question

I have defined an interface like this   interface IModal       content  string      form  string      href  string       form  JQuery       message  JQuery       modal  JQuery       submits  JQuery       I define a variable like this   var modal  IModal    However  when I try to set the property of modal it gives me a message saying that    cannot set property content of undefined    Is it okay to use an interface to describe my modal object and if so how should I create it

User · Answer

Using your interface you can do  class Modal       constructor public iModal  IModal         You now have access to all your interface variables using this iModal object       you don t need to define the properties at all  constructor does it for you

User · Answer

If you want an empty object of an interface  you can do just   var modal    lt IModal gt       The advantage of using interfaces in lieu of classes for structuring data is that if you don t have any methods on the class  it will show in compiled JS as an empty method  Example   class TestClass       a  number      b  string      c  boolean      compiles into  var TestClass    function          function TestClass               return TestClass          which carries no value  Interfaces  on the other hand  don t show up in JS at all while still providing the benefits of data structuring and type checking

User · Answer

If you are creating the  modal  variable elsewhere  and want to tell TypeScript it will all be done  you would use   declare const modal  IModal    If you want to create a variable that will actually be an instance of IModal in TypeScript you will need to define it fully   const modal  IModal         content          form          href           form  null       message  null       modal  null       submits  null      Or lie  with a type assertion  but you ll lost type safety as you will now get undefined in unexpected places  and possibly runtime errors  when accessing modal content and so on  properties that the contract says will be there    const modal      as IModal    Example Class  class Modal implements IModal       content  string      form  string      href  string       form  JQuery       message  JQuery       modal  JQuery       submits  JQuery     const modal   new Modal      You may think  hey that s really a duplication of the interface  - and you are correct  If the Modal class is the only implementation of the IModal interface you may want to delete the interface altogether and use     const modal  Modal   new Modal      Rather than  const modal  IModal   new Modal

User · Answer

Here another solution what i am using frequently  However I am not sure is good practice or not  please comment below if not      Interface export default interface BookInterface     title  string    author  string    id  any        Creating Class export class BookClass implements BookInterface     title  string    author  string    id  any     constructor title  string  author  string  id  any        this title   title      this author   author      this id   id             How to use it let book  BookInterface   new BookClass title  author  id    Thanks

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Many of the solutions so far posted use type assertions and therefor do not throw compilation errors if required interface properties are omitted in the implementation   For those interested in some other robust  compact solutions   Option 1  Instantiate an anonymous class which implements the interface   new class implements MyInterface     nameFirst    John     nameFamily    Smith          Option 2  Create a utility function   export function impl lt I gt  i  I    return i     impl lt MyInterface gt      nameFirst   John     nameFamily   Smith

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If you are using React  the parser will choke on the traditional cast syntax so an alternative was introduced for use in  tsx files  let a      as MyInterface    https   www typescriptlang org docs handbook jsx html

User · Answer

Since I haven t found an equal answer in the top and my answer is different  I do   modal  IModal    lt IModal gt

User · Answer

You can set default values using Class   Without Class Constructor   interface IModal     content  string    form  string    href  string    isPopup  boolean      class Modal implements IModal     content         form         href  string      will not be added to object   isPopup   true     const myModal   new Modal    console log myModal      output   content      form      isPopup  true    With Class Constructor  interface IModal     content  string    form  string    href  string    isPopup  boolean     class Modal implements IModal     constructor         this content           this form           this isPopup   true         content  string     form  string     href  string     not part of constructor so will not be added to object    isPopup  boolean     const myModal   new Modal    console log myModal      output   content      form      isPopup  true

User · Answer

I think you have basically five different options to do so  Choosing among them could be easy depending on the goal you would like to achieve    The best way in most of the cases to use a class and instantiate it  because you are using TypeScript to apply type checking   interface IModal       content  string      form  string                   Extra     foo   bar  string   void     class Modal implements IModal       content  string      form  string       foo param  string   void             Even if other methods are offering easier ways to create an object from an interface you should consider splitting your interface apart  if you are using your object for different matters  and it does not cause interface over-segregation    interface IBehaviour         Extra     foo param  string   void     interface IModal extends IBehaviour      content  string      form  string                On the other hand  for example during unit testing your code  if you may not applying separation of concerns frequently   you may be able to accept the drawbacks for the sake of productivity  You may apply other methods to create mocks mostly for big third party   d ts interfaces  And it could be a pain to always implement full anonymous objects for every huge interface   On this path your first option is to create an empty object    var modal    lt IModal gt       Secondly to fully realise the compulsory part of your interface  It can be useful whether you are calling 3rd party JavaScript libraries  but I think you should create a class instead  like before   var modal  IModal         content          form                     foo   param  string   void   gt               Thirdly you can create just a part of your interface and create an anonymous object  but this way you are responsible to fulfil the contract  var modal  IModal    lt any gt       foo   param  string   void   gt                Summarising my answer even if interfaces are optional  because they are not transpiled into JavaScript code  TypeScript is there to provide a new level of abstraction  if used wisely and consistently  I think  just because you can dismiss them in most of the cases from your own code you shouldn t

User · Answer

You can do  var modal      as IModal

User · Answer

Here is another approach   You can simply create an ESLint friendly object like this  const modal  IModal      as IModal    Or a default instance based on the interface and with sensible defaults  if any  const defaultModal  IModal         content          form          href           form     as JQuery       message     as JQuery       modal     as JQuery       submits     as JQuery      Then variations of the default instance simply by overriding some properties  const confirmationModal  IModal            defaultModal         all properties values from defaultModal     form   confirmForm      override form only

[typescript] How can I create an object based on an interface file definition in TypeScript?

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