How to configure welcome file list in web xml

Question

I have this in my web xml document  I am trying to have a welcome list so I dont need to type the path for the home page anymore  But everytime a clicked the application in my tomcat page it displays The requested resource is not available    lt listener gt       lt listener-class gt web Init lt  listener-class gt   lt  listener gt    lt welcome-file-list gt       lt welcome-file gt index jsp lt  welcome-file gt   lt  welcome-file-list gt    lt servlet gt       lt servlet-name gt index lt  servlet-name gt       lt servlet-class gt web IndexServlet lt  servlet-class gt   lt  servlet gt    lt servlet-mapping gt       lt servlet-name gt index lt  servlet-name gt       lt url-pattern gt  index lt  url-pattern gt   lt  servlet-mapping gt    My servlet for the jsp page   package web   import java io IOException   import javax servlet RequestDispatcher  import javax servlet ServletConfig  import javax servlet ServletContext  import javax servlet ServletException  import javax servlet http HttpServlet  import javax servlet http HttpServletRequest  import javax servlet http HttpServletResponse   import org apache log4j Logger   public class IndexServlet extends HttpServlet       private Logger logger   Logger getLogger this getClass         private RequestDispatcher jsp       public void init ServletConfig config  throws ServletException               ServletContext context   config getServletContext            jsp   context getRequestDispatcher   WEB-INF jsp index jsp               protected void doGet HttpServletRequest req  HttpServletResponse resp  throws ServletException  IOException               logger debug  doGet              jsp forward req  resp              Why is that it is still not working I still need to type the  index in my url   How to do this correctly

User · Answer

You need to put the JSP file in  index jsp instead of in  WEB-INF jsp index jsp  This way the whole servlet is superflous by the way   WebContent   -- META-INF   -- WEB-INF        -- web xml   -- index jsp   If you re absolutely positive that you need to invoke a servlet this strange way  then you should map it on an URL pattern of  index jsp instead of  index  You only need to change it to get the request dispatcher from request instead of from config and get rid of the whole init   method   In case you actually intend to have a  home page servlet   and thus not a welcome file  mdash  which has an entirely different purpose  namely the default file which sould be served when a folder is being requested  which is thus not specifically the root folder   then you should be mapping the servlet on the empty string URL pattern    lt servlet-mapping gt       lt servlet-name gt index lt  servlet-name gt       lt url-pattern gt  lt  url-pattern gt   lt  servlet-mapping gt    See also Difference between   and    in servlet mapping url pattern

User · Answer

I guess what you want is your index servlet to act as the welcome page  so change to    lt welcome-file-list gt      lt welcome-file gt index lt  welcome-file gt   lt  welcome-file-list gt    So that the index servlet will be used   Note  you ll need a servlet spec 2 4 container to be able to do this   Note also   BalusC gets my vote  for your index servlet on its own is superfluous

User · Answer

I simply declared as below in web xml file and Its working for me      lt welcome-file-list gt       lt welcome-file gt  WEB-INF jsps index jsp lt  welcome-file gt   lt  welcome-file-list gt    And NO html jsp pages present in public directory except static resources css  js  images   Now I can access my index page with URL like   http   localhost 8080 app  Its calling   WEB-INF jsps index jsp page   When hosted live in production the final URL looks like https   eisdigital com

User · Answer

I saw a nice solution in this stackoverflow link that may help the readers of the defulat servlet handling issue by using the empty string URL pattern         WebServlet       or   lt servlet-mapping gt       lt servlet-name gt yourHomeServlet lt  servlet-name gt       lt url-pattern gt  lt  url-pattern gt   lt  -- Yes  empty string  -- gt   lt  servlet-mapping gt

User · Answer

Its based on from which file you are trying to access those files   If it is in the same folder where your working project file is  then you can use just the file name  no need of path   If it is in the another folder which is under the same parent folder of your working project file then you can use location like in the following  javascript sample js  In your example if you are trying to access your js file from your html file you can use the following location     javascript sample js  the prefix    will go to the parent folder of the file Folder upward journey

User · Answer

This is my way to setup Servlet as welcome page   I share for whom concern   web xml     lt welcome-file-list gt           lt welcome-file gt index jsp lt  welcome-file gt       lt  welcome-file-list gt       lt servlet gt           lt servlet-name gt Demo lt  servlet-name gt           lt servlet-class gt servlet Demo lt  servlet-class gt       lt  servlet gt       lt servlet-mapping gt           lt servlet-name gt Demo lt  servlet-name gt           lt url-pattern gt  lt  url-pattern gt       lt  servlet-mapping gt    Servlet class   WebServlet name     demo   public class Demo extends HttpServlet      public void doGet HttpServletRequest req  HttpServletResponse res       throws ServletException  IOException           RequestDispatcher rd   req getRequestDispatcher  index jsp

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