Convert command line argument to string

Question

I have a program that reads hard-coded file-path and I want to make it read file-path from command line instead  For that purpose I changed the code like this    include  lt iostream gt   int main char  argv              but  argv 1  variable exposed this way seems to be of type pointer  and I need it as a string  What should I do to convert this command line argument to string

User · Accepted Answer

It s already an array of C-style strings    include  lt iostream gt   include  lt string gt   include  lt vector gt    int main int argc  char  argv       Don t forget first integral argument  argc      std  string current exec name   argv 0      Name of the current exec program   std  vector lt std  string gt  all args     if  argc  gt  1        all args assign argv   1  argv   argc           Argument argc is count of arguments plus the current exec file

User · Answer

include  lt iostream gt   std  string commandLineStr      for  int i 1 i lt argc i    commandLineStr append std  string argv i   append

User · Answer

No need to upvote this  It would have been cool if Benjamin Lindley made his one-liner comment an answer  but since he hasn t  here goes   std  vector lt std  string gt  argList argv  argv   argc    If you don t want to include argv 0  so you don t need to deal with the executable s location  just increment the pointer by one   std  vector lt std  string gt  argList argv   1  argv   argc

User · Answer

It s simple  Just do this    include  lt iostream gt   include  lt vector gt   include  lt string h gt   int main int argc  char  argv          std  vector lt std  string gt  argList      for int i 0 i lt argc i            argList push back argv i          now you can access argList n       Benjamin Lindley You are right  This is not a good solution  Please read the one answered by juanchopanza

User · Answer

Because all attempts to print the argument I placed in my variable failed  here my 2 bytes for this question   std  string dump name    stuff     if argc gt 2        dump name assign argv 2        fprintf stdout   ARGUMENT  s   dump name c str         Note the use of assign  and also the need for the c str   function call

User · Answer

I m not sure if this is 100  portable but the way the OS SHOULD parse the args is to scan through the console command string and insert a nil-term char at the end of each token  and int main int char    doesn t use const char   so we can just iterate through the args starting from the third argument   note the first arg is the working directory  and scan backward to the nil-term char and turn it into a space rather than start from beginning of the second argument and scanning forward to the nil-term char  Here is the function with test script  and if you do need to un-nil-ify more than one nil-term char then please comment so I can fix it  thanks    include  lt cstdio gt   include  lt iostream gt   using namespace std   namespace        Converts int main int char    arguments back into a string   return false if there are no args to convert   param arg count The number of arguments   param args      The arguments     bool ArgsToString int args count  char   args      if  args count  lt   1  return false    if  args count    2  return true    for  int i   2  i  lt  args count    i        char  cursor   args i       while   cursor  --cursor       cursor              return true          namespace    int main int args count  char   args      cout  lt  lt    n nTesting ArgsToString    n      if  args count  lt   1  return 1    cout  lt  lt    nArguments  n     for  int i   0  i  lt  args count    i        char  arg   args i       printf   ni  i   s   0x p   i  arg  arg         cout  lt  lt    n nContiguous Args  n     char  end   args args count - 1     while   end    end    cout  lt  lt    n nContiguous Args  n     char  cursor   args 0     while  cursor    end        char c    cursor        if  c    0        cout  lt  lt           else if  c  lt             cout  lt  lt           else       cout  lt  lt  c        cout  lt  lt    n nPrinting argument string    n        ArgsToString args count  args     cout  lt  lt    n   lt  lt  args 1     return 0

User · Answer

You can create an std  string   include  lt string gt   include  lt vector gt  int main int argc  char  argv           check if there is more than one argument and use the second one        the first argument is the executable    if  argc  gt  1          std  string arg1 argv 1           do stuff with arg1           Or  copy all arguments into a container of strings   std  vector lt std  string gt  allArgs argv  argv   argc

[c++] Convert command line argument to string

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