Is there a way to print an exception message in Java without the exception?
When I try the following piece of code:
try {
// statements
} catch (javax.script.ScriptException ex) {
System.out.println(ex.getMessage());
}
The output is:
Invalid JavaScript code: sun.org.mozilla.javascript.internal.EvaluatorException:
missing } after property list (<Unknown source>) in <Unknown source>;
at line number 1
Is there a way to print the message without the exception information, source and line number information. In other words, the message I would like to print in the output is:
missing } after property list
This question is related to
java
exception-handling
The output looks correct to me:
Invalid JavaScript code: sun.org.mozilla.javascript.internal.EvaluatorException: missing } after property list (<Unknown source>) in <Unknown source>; at line number 1
I think Invalid Javascript code: ..
is the start of the exception message.
Normally the stacktrace isn't returned with the message:
try {
throw new RuntimeException("hu?\ntrace-line1\ntrace-line2");
} catch (Exception e) {
System.out.println(e.getMessage()); // prints "hu?"
}
So maybe the code you are calling catches an exception and rethrows a ScriptException
. In this case maybe e.getCause().getMessage()
can help you.
try {
} catch (javax.script.ScriptException ex) {
// System.out.println(ex.getMessage());
}
Source: Stackoverflow.com