how to parse xml to java object

Question

I have a XML which is used to config some rules  it does not has complex structure  but this configuration is used anywhere in my system  so I want to parse this XML to java object and design as singleton mode  is any good way I can use it to unmarshal XML to Java object directly without write much codes   I did some research on Google and known JAXB is a choice  my application is just some kinds of tool program which read rule and then follow do stuffs  JAXB could be used for web service more widely  it fit my projects    If yes  the most important question is  I used xjc to generate java object source class according xsd file  after unmarshal I will directly get these configurationType object  is it necessary I convert again   from the JaxB classes to my owned java pojo object configuration   I see most coder did this  but why  because they are some data  just from the object generated to JAXB and copy to ourself created POJO object

User · Answer

I find jackson fasterxml is one good choice to serializing deserializing bean with XML   Refer  How to use spring to marshal and unmarshal xml

User · Answer

JAXB is a reliable choice as it does xml to java classes mapping smoothely  But there are other frameworks available  here is one such   https   code google com p xmappr

User · Answer

JAXB is an ideal solution  But you do not necessarily need xsd and xjc for that  More often than not you don t have an xsd but you know what your xml is  Simply analyze your xml  e g     lt customer id  100  gt       lt age gt 29 lt  age gt       lt name gt mkyong lt  name gt   lt  customer gt    Create necessary model class es     XmlRootElement public class Customer        String name      int age      int id       public String getName             return name              XmlElement     public void setName String name            this name   name             public int getAge             return age              XmlElement     public void setAge int age            this age   age             public int getId             return id              XmlAttribute     public void setId int id            this id   id             Try to unmarshal   JAXBContext jaxbContext   JAXBContext newInstance Customer class   Unmarshaller jaxbUnmarshaller   jaxbContext createUnmarshaller    Customer customer    Customer  jaxbUnmarshaller unmarshal new File  C   file xml       Check results  fix bugs

User · Answer

For performing Unmarshall using JAXB   1  Convert given XML to XSD by yourself or by online convertor    2  Create a JAXB project in eclipse   3  Create XSD file and paste that converted XSD content in it   4  Right click on   XSD file--  Generate--  JAXB Classes-- follow the instructions this will      create all nessasary  java files in src  i e   one package-info  object factory and pojo class    5  Create another  java file in src to operate unmarshall operation  and run it   Happy Coding

User · Answer

One thing that is really important to understand considering you have an XML file as      lt customer id  100  gt       lt Age gt 29 lt  Age gt       lt NAME gt mkyong lt  NAME gt   lt  customer gt    I am sorry to inform you but     XmlElement public void setAge int age        this age   age      will not help you  as it tries to look for  age  instead of  Age  element name from the XML   I encourage you to manually specify the element name matching the one in the XML file     XmlElement name  Age   public void setAge int age        this age   age      And if you have for example      XmlRootElement  XmlAccessorType  XmlAccessType FIELD  public class Customer         It means it will use java beans by default  and at this time if you specify  that you must not set another     XmlElement name  NAME      annotation above a setter method for an element  lt NAME gt    lt  NAME gt  it will fail saying that there cannot be two elements on one single variables   I hope that it helps

[java] how to parse xml to java object?

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