[javascript] Is there a C# String.Format() equivalent in JavaScript?

C# has the really powerful String.Format() for replacing elements like {0}with parameters. Does JavaScript have an equivalent?

This question is related to javascript

The answer is


I am using:

String.prototype.format = function() {
    var s = this,
        i = arguments.length;

    while (i--) {
        s = s.replace(new RegExp('\\{' + i + '\\}', 'gm'), arguments[i]);
    }
    return s;
};

usage: "Hello {0}".format("World");

I found it at Equivalent of String.format in JQuery

UPDATED:

In ES6/ES2015 you can use string templating for instance

'use strict';

let firstName = 'John',
    lastName = 'Smith';

console.log(`Full Name is ${firstName} ${lastName}`); 
// or
console.log(`Full Name is ${firstName + ' ' + lastName}');

Based on @Vlad Bezden answer I use this slightly modified code because I prefer named placeholders:

String.prototype.format = function(placeholders) {
    var s = this;
    for(var propertyName in placeholders) {
        var re = new RegExp('{' + propertyName + '}', 'gm');
        s = s.replace(re, placeholders[propertyName]);
    }    
    return s;
};

usage:

"{greeting} {who}!".format({greeting: "Hello", who: "world"})

_x000D_
_x000D_
String.prototype.format = function(placeholders) {_x000D_
    var s = this;_x000D_
    for(var propertyName in placeholders) {_x000D_
        var re = new RegExp('{' + propertyName + '}', 'gm');_x000D_
        s = s.replace(re, placeholders[propertyName]);_x000D_
    }    _x000D_
    return s;_x000D_
};_x000D_
_x000D_
$("#result").text("{greeting} {who}!".format({greeting: "Hello", who: "world"}));
_x000D_
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>_x000D_
<div id="result"></div>
_x000D_
_x000D_
_x000D_


I created it a long time ago, related question

String.Format = function (b) {
    var a = arguments;
    return b.replace(/(\{\{\d\}\}|\{\d\})/g, function (b) {
        if (b.substring(0, 2) == "{{") return b;
        var c = parseInt(b.match(/\d/)[0]);
        return a[c + 1]
    })
};